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二叉树.cpp
269 lines (255 loc) · 5.71 KB
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二叉树.cpp
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/*二叉树的相关操作(数据结构),C语言描述*/
#include "myhead.h"
#define stacksize 30
typedef struct treenode{
int data;
struct treenode *left,*right;
}Tree,*TREE;
typedef struct{
TREE *base;
TREE *top;
int size;
}Sqstack;
typedef struct qnode{
TREE data;
struct qnode *next;
}Qnode,*Queue;
typedef struct {
Queue front;
Queue rear;
}LinkQueue;
int print(int e){
printf("%d ",e);
return 1;
}
void initstack(Sqstack *S){
(*S).base=(TREE *)malloc(stacksize*sizeof(TREE));
if(!(*S).base) exit(0);
(*S).top=(*S).base;
(*S).size=stacksize;
}
void push(Sqstack *S,TREE e){
if((*S).top-(*S).base>=(*S).size){
(*S).base=(TREE *)realloc((*S).base,((*S).size+5)*sizeof(TREE));
(*S).top=(*S).base+(*S).size;
(*S).size+=5;
}
*(*S).top++=e;
}
void pop(Sqstack *S,TREE *e){ *e=*(--(*S).top); }
int stackempty(Sqstack S){
if(S.base==S.top) return 0;
else return 1;
}
void initqueue(LinkQueue *Q){
(*Q).front=(*Q).rear=(Queue)malloc(sizeof(Qnode));
if(!(*Q).front) exit(0);
(*Q).front->next=NULL;
}
void inqueue(LinkQueue *Q,TREE e){
Queue p;
p=(Queue)malloc(sizeof(Qnode));
if(!p) exit(0);
p->data=e;p->next=NULL;
(*Q).rear->next=p;
(*Q).rear=p;
}
void outqueue(LinkQueue *Q,TREE *e){
Queue p;
p=(*Q).front->next;
*e=p->data;
(*Q).front->next=p->next;
if((*Q).rear==p) (*Q).rear=(*Q).front;
free(p);
}
int queueempty(LinkQueue Q){
if(Q.front==Q.rear) return 0;
else return 1;
}
int n0=0,n1=0,n2=0;
void creattree(TREE *T);
void pretraverse1(TREE T);
void pretraverse2(TREE T);
int intraverse1(TREE T);
void intraverse2(TREE T);
int posttraverse1(TREE T);
int outdegree1(TREE T);
void outdegree2(TREE T);
void floortraverse(TREE T);
int hight(TREE T);
void exchange(TREE *T);
int menu(){
int choice;
printf("%*s",30,"1.前序遍历,递归算法(11),非递归算法(12)\n");
printf("2.中序遍历,递归算法(21),非递归算法(22)\n");
printf("3.后序遍历,递归算法\n");
printf("4.求度分别为0、1、2的节点数目,递归算法(41),非递归算法(42)\n");
printf("5.按层次遍历二叉树\n");
printf("6.求二叉树的高度\n");
printf("7.交换每个结点的左右子树,并中序遍历\n");
printf("请选择:");
scanf("%d",&choice);
return choice;
}
int binatTreeMain(){
TREE T;
int choice;
char c='y';
printf("请输入带空二叉树先序遍历序列(0表示空节点),例如3个元素的二叉树输入为\n");
printf(" 1 2 0 0 3 0 0 (1为根结点):");
creattree(&T);
while(c=='Y'||c=='y'){
choice=menu();
switch(choice){
case 11:printf("递归法前序遍历:");pretraverse1(T);break;
case 12:printf("非递归法前序遍历:");pretraverse2(T);break;
case 21:printf("递归法中序遍历:");intraverse1(T);break;
case 22:printf("非递归法中序遍历:");intraverse2(T);break;
case 3:printf("递归法后序遍历:");posttraverse1(T);break;
case 41:outdegree1(T);
printf("出度为0的节点数目:%d\n",n0);
printf("出度为1的节点数目:%d\n",n1);
printf("出度为2的节点数目:%d\n",n2);break;
case 42:outdegree2(T);break;
case 5:floortraverse(T);break;
case 6:printf("\n此二叉树高度为:%d",hight(T));break;
case 7:exchange(&T);intraverse1(T);break;
}
printf("\n是否继续?(Y/N):");
fflush(stdin);
scanf("%c",&c);
system("cls");
}
}
void creattree(TREE *T){
int d;
scanf("%d",&d);
if(d==0) (*T)=NULL;
else{
if(!((*T)=(TREE)malloc(sizeof(Tree)))) exit(0);
(*T)->data=d;
creattree(&((*T)->left));
creattree(&((*T)->right));
}
}
void pretraverse1(TREE T){
if(T){
print(T->data);
pretraverse1(T->left);
pretraverse1(T->right);
}
}
void pretraverse2(TREE T){
TREE p;
Sqstack S;
initstack(&S);p=T;
while(p||stackempty(S)){//节点不为空或者栈不空时循环
if(p) {
print(p->data);
push(&S,p);
p=p->left;
}
else{
pop(&S,&p);
p=p->right;
}
}
}
int intraverse1(TREE T){
if(T){
if(intraverse1(T->left))
if(print(T->data))
if(intraverse1(T->right)) return 1;
}
else return 1;
}
void intraverse2(TREE T){
TREE p;
Sqstack S;
initstack(&S);p=T;
while(p||stackempty(S)){//节点不为空或者栈不空时循环
if(p) {
push(&S,p);
p=p->left;
}
else{
pop(&S,&p);
print(p->data);
p=p->right;
}
}
}
int posttraverse1(TREE T){
if(T){
if(posttraverse1(T->left))
if(posttraverse1(T->right))
if(print(T->data)) return 1;
}
else return 1;
}
int outdegree1(TREE T){
int flag1=0,flag2=0;
if(T){
if(outdegree1(T->left))
if(outdegree1(T->right)){
if(T->left) flag1=1;
if(T->right) flag2=1;
if(flag1&&flag2) n2++;
else if(!flag1&&!flag2) n0++;
else n1++;
}
flag1=flag2=0; return 1;
}
else return 1;
}
void outdegree2(TREE T){
TREE p;
LinkQueue Q;
int flag1=0,flag2=0,n0=0,n1=0,n2=0;
initqueue(&Q);p=T;
inqueue(&Q,p);
while(queueempty(Q)){
outqueue(&Q,&p);
if(p->left) {inqueue(&Q,p->left);flag1=1;}
if(p->right){inqueue(&Q,p->right);flag2=1;}
if(flag1&&flag2) n2++;
else if(!flag1&&!flag2) n0++;
else n1++;
flag1=flag2=0;
}
printf("出度为0的节点数目:%d\n",n0);
printf("出度为1的节点数目:%d\n",n1);
printf("出度为2的节点数目:%d\n",n2);
}
void floortraverse(TREE T){
TREE p;
LinkQueue Q;
initqueue(&Q);p=T;
inqueue(&Q,p);
while(queueempty(Q)){
outqueue(&Q,&p);
print(p->data);
if(p->left) inqueue(&Q,p->left);
if(p->right) inqueue(&Q,p->right);
}
}
int h=0,maxh=0;
int hight(TREE T)
{
h++;
if(maxh<h) maxh=h;
if(T){
hight(T->left);
hight(T->right);
}
h--;
return maxh-1;
}
void exchange(TREE *T)
{
TREE p;
if(!(*T)) return;
p=(*T)->left;(*T)->left=(*T)->right;(*T)->right=p;
exchange(&((*T)->left));
exchange(&((*T)->right));
}