int diehard_squeeze(Test **test, int irun)
{
int i,j,k;
Vtest vtest;
/*
* Squeeze counts the iterations required to reduce 2^31 to
* to 1 with k = ceiling(k*U) where U is a uniform deviate. It
* does this test[0]->tsamples times, binning the result in a vector from
* <= 6 to >= 48 (where it has nontrivial support). A chisq test
* on the vector (Vtest) then yields a pvalue for the test run.
*/
/*
* for display only. 0 means "ignored".
*/
test[0]->ntuple = 0;
/*
* Allocate memory for Vtest struct vector (length 51) and initialize
* it with the expected values.
*/
Vtest_create(&vtest,43);
/*
* Initialize the expected value vector
*/
vtest.cutoff = 5.0;
for(i=0;i<43;i++){
vtest.y[i] = test[0]->tsamples*sdata[i];
}
memset(vtest.x,0,43*sizeof(double));
/*
* Test this.
*/
MYDEBUG(D_DIEHARD_SQUEEZE) {
for(i=0;i<43;i++){
printf("%d: %f %f\n",i+6,vtest.x[i],vtest.y[i]);
}
}
/*
* We now squeeze test[0]->tsamples times.
*/
for(i=0;i<test[0]->tsamples;i++){
k = 2147483647;
j = 0;
/* printf("%d: %d\n",j,k); */
while((k != 1) && (j < 48)){
k = ceil(k*gsl_rng_uniform(rng));
j++;
/* printf("%d: %d\n",j,k); */
}
/*
* keep j in range 6-48 inclusive and increment the test/counting vector.
*/
j = (j<6)?6:j;
vtest.x[j-6]++;
}
MYDEBUG(D_DIEHARD_SQUEEZE) {
for(i=0;i<43;i++){
printf("%d: %f %f\n",i+6,vtest.x[i],vtest.y[i]);
}
}
Vtest_eval(&vtest);
test[0]->pvalues[irun] = vtest.pvalue;
MYDEBUG(D_DIEHARD_SQUEEZE) {
printf("# diehard_squeeze(): test[0]->pvalues[%u] = %10.5f\n",irun,test[0]->pvalues[irun]);
}
Vtest_destroy(&vtest);
return(0);
}
int diehard_count_1s_byte(Test **test, int irun)
{
uint i,j,k,index5=0,index4,letter,t;
uint boffset;
uint count5[3125],count4[625];
Vtest vtest4,vtest5;
Xtest ptest;
/*
* count_1s in specific bytes is straightforward after looking over
* count_1s in a byte. The statistic is identical; we just have to
* cycle the offset of the bytes selected and generate 1 random uint
* per digit.
*/
/*
* I'm leaving this in so the chronically bored can validate that
* the table exists and is correctly loaded and addressable.
*/
if(verbose == -1){
for(i=0;i<256;i++){
printf("%u, ",b5b[i]);
/* dumpbits(&i,8); */
if((i+1)%16 == 0){
printf("\n");
}
}
exit(0);
}
/*
* for display only. 0 means "ignored".
*/
test[0]->ntuple = 0;
/*
* This is basically a pair of parallel vtests, with a final test
* statistic generated from their difference (somehow). We therefore
* create two vtests, one for four digit base 5 integers and one for
* five digit base 5 integers, and generate their expected values for
* test[0]->tsamples trials.
*/
ptest.y = 2500.0;
ptest.sigma = sqrt(5000.0);
Vtest_create(&vtest4,625);
vtest4.cutoff = 5.0;
for(i=0;i<625;i++){
j = i;
vtest4.y[i] = test[0]->tsamples;
vtest4.x[i] = 0.0;
/*
* Digitize base 5, compute expected value for THIS integer i.
*/
/* printf("%u: ",j); */
for(k=0;k<4;k++){
/*
* Take the least significant "letter" of j in range 0-4
*/
letter = j%5;
/*
* multiply by the probability of getting this letter
*/
vtest4.y[i] *= pb[letter];
/*
* Right shift j to get next digit.
*/
/* printf("%1u",letter); */
j /= 5;
}
/* printf(" = %f\n",vtest4.y[i]); */
}
Vtest_create(&vtest5,3125);
vtest5.cutoff = 5.0;
for(i=0;i<3125;i++){
j = i;
vtest5.y[i] = test[0]->tsamples;
vtest5.x[i] = 0.0;
/*
* Digitize base 5, compute expected value for THIS integer i.
*/
for(k=0;k<5;k++){
/*
* Take the least significant "letter" of j in range 0-4
*/
letter = j%5;
/*
* multiply by the probability of getting this letter
*/
vtest5.y[i] *= pb[letter];
/*
* Right shift j to get next digit.
*/
j /= 5;
}
}
/*
* Here is the test. We cycle boffset through test[0]->tsamples
*/
boffset = 0;
for(t=0;t<test[0]->tsamples;t++){
boffset = t%32; /* Remember that get_bit_ntuple periodic wraps the uint */
/*
* Get the next five bytes and make an index5 out of them, no
* overlap.
*/
for(k=0;k<5;k++){
i = get_rand_bits_uint(32, 0xFFFFFFFF, rng);
if(verbose == D_DIEHARD_COUNT_1S_STREAM || verbose == D_ALL){
dumpbits(&i,32);
}
/*
* get next byte from the last rand we generated.
* Bauer fix -
* Cruft: j = get_bit_ntuple_from_uint(i,8,0x000000FF,boffset);
*/
j = get_bit_ntuple_from_whole_uint(i,8,0x000000FF,boffset);
index5 = LSHIFT5(index5,b5b[j]);
if(verbose == D_DIEHARD_COUNT_1S_STREAM || verbose == D_ALL){
printf("b5b[%u] = %u, index5 = %u\n",j,b5b[j],index5);
dumpbits(&j,8);
}
}
/*
* We use modulus to throw away the sixth digit in the left-shifted
* base 5 index value, keeping the value of the 5-digit base 5 number
* in the range 0 to 5^5-1 or 0 to 3124 decimal. We repeat for the
* four digit index. At this point we increment the counts for index4
* and index5. Tres simple, no?
*/
index5 = index5%3125;
index4 = index5%625;
vtest4.x[index4]++;
vtest5.x[index5]++;
}
/*
* OK, all that is left now is to figure out the statistic.
*/
if(verbose == D_DIEHARD_COUNT_1S_BYTE || verbose == D_ALL){
for(i = 0;i<625;i++){
printf("%u: %f %f\n",i,vtest4.y[i],vtest4.x[i]);
}
for(i = 0;i<3125;i++){
printf("%u: %f %f\n",i,vtest5.y[i],vtest5.x[i]);
}
}
Vtest_eval(&vtest4);
Vtest_eval(&vtest5);
if(verbose == D_DIEHARD_COUNT_1S_BYTE || verbose == D_ALL){
printf("vtest4.chisq = %f vtest5.chisq = %f\n",vtest4.chisq,vtest5.chisq);
}
ptest.x = vtest5.chisq - vtest4.chisq;
Xtest_eval(&ptest);
test[0]->pvalues[irun] = ptest.pvalue;
MYDEBUG(D_DIEHARD_COUNT_1S_BYTE) {
printf("# diehard_count_1s_byte(): test[0]->pvalues[%u] = %10.5f\n",irun,test[0]->pvalues[irun]);
}
Vtest_destroy(&vtest4);
Vtest_destroy(&vtest5);
return(0);
}
double diehard_rank_6x8(QVector<double> const &sample)
{
rng = gsl_rng_alloc(gsl_rng_taus);
int i = 0;
int t = 0;
int rank = 0;
uint bitstring;
Vtest vtest;
uint **mtx;
mtx = new uint * [6];
for (i = 0; i < 6; i++){
mtx[i] = new uint [8];
}
Vtest_create(&vtest, 7);
vtest.cutoff = 5.0;
for (i = 0; i < 2; i++){
vtest.x[i] = 0.0;
vtest.y[i] = 0.0;
}
vtest.x[2] = 0.0;
vtest.y[2] = sample[1];
vtest.x[3] = 0.0;
vtest.y[3] = sample[2];
vtest.x[4] = 0.0;
vtest.y[4] = sample[3];
vtest.x[5] = 0.0;
vtest.y[5] = sample[4];
vtest.x[6] = 0.0;
vtest.y[6] = sample[5];
double r = 0;
for (t = 0; t < 6; t++) {
/*
* We generate 6 random rmax_bits-bit integers and put a
* randomly chosen byte into the LEFTMOST byte position
* of the row/slot of mtx.
*/
for (i = 0; i < 6; i++){
bitstring = get_rand_bits_uint(32, 0xffffffff, rng);
mtx[i][0] = bitstring;
}
rank = binary_rank(mtx, 6, 8);
r += rank;
//MYDEBUG(D_DIEHARD_RANK_6x8){
// printf("binary rank = %d\n", rank);
//}
if (rank <= 2) {
vtest.x[2]++;
}
else {
vtest.x[rank]++;
}
}
Vtest_eval(&vtest);
int result = vtest.pvalue;
Vtest_destroy(&vtest);
for (i = 0; i < 6; i++) {
delete [] mtx[i];
}
delete [] mtx;
gsl_rng_free(rng);
return r / 6.0 ;
}