int main(void)
{
//Note: x%3 == 0 exactly when x evenly divisible by 3
// and x%5 == 0 when x divisible by 5
int n;
n=1000;
printf("The sum through %d is...\nTake1: %d\nTake2: %d\nTake3: %d\n",
n, take1(n), take2(n), take3(n));
return 0;
}
int main()
{
int num;
int count = 0;
TMOD=0x01;
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
EA=1;
ET0=1; //开中断
TR0=1;
init();
P2=0xff;
st: lock=0;
while(1)
{
write_com(0x01);
write_lcd(0x40,"save take");
num = key();
if(num == 10) //存放模式
{
NO1 = TH0;
NO2 = TL0;
save2();
}
if(num == 11) //取出模式
{
take2();
}
if(lock>4)
{
lk: write_com(0x01);
write_lcd(0x00," lock on! ");
while(1)
{
if(key() == 13)
{
write_lcd(0x00,"admin: ");
if(admin_key() == 1)
{
lock = 0;
goto st;
}
goto lk;
}
}
}
}
return 0;
}
