Beispiel #1
0
RangeList<T> subtract (Range<T> range, RangeList<T> sub)
{
	/* Start with the input range */
	RangeList<T> result;
	result.add (range);

	if (sub.empty () || range.empty()) {
		return result;
	}

	typename RangeList<T>::List s = sub.get ();

	/* The basic idea here is to keep a list of the result ranges, and subtract
	   the bits of `sub' from them one by one.
	*/
	
	for (typename RangeList<T>::List::const_iterator i = s.begin(); i != s.end(); ++i) {

		/* Here's where we'll put the new current result after subtracting *i from it */
		RangeList<T> new_result;

		typename RangeList<T>::List r = result.get ();

		/* Work on all parts of the current result using this range *i */
		for (typename RangeList<T>::List::const_iterator j = r.begin(); j != r.end(); ++j) {

			switch (coverage (j->from, j->to, i->from, i->to)) {
			case OverlapNone:
				/* The thing we're subtracting (*i) does not overlap this bit of the result (*j),
				   so pass it through.
				*/
				new_result.add (*j);
				break;
			case OverlapInternal:
				/* Internal overlap of the thing we're subtracting (*i) from this bit of the result,
				   so we should end up with two bits of (*j) left over, from the start of (*j) to
				   the start of (*i), and from the end of (*i) to the end of (*j).
				*/
				assert (j->from < i->from);
				assert (j->to > i->to);
				new_result.add (Range<T> (j->from, i->from - 1));
				new_result.add (Range<T> (i->to + 1, j->to));
				break;
			case OverlapStart:
				/* The bit we're subtracting (*i) overlaps the start of the bit of the result (*j),
				 * so we keep only the part of of (*j) from after the end of (*i)
				 */
				assert (i->to < j->to);
				new_result.add (Range<T> (i->to + 1, j->to));
				break;
			case OverlapEnd:
				/* The bit we're subtracting (*i) overlaps the end of the bit of the result (*j),
				 * so we keep only the part of of (*j) from before the start of (*i)
				 */
				assert (j->from < i->from);
				new_result.add (Range<T> (j->from, i->from - 1));
				break;
			case OverlapExternal:
				/* total overlap of the bit we're subtracting with the result bit, so the
				   result bit is completely removed; do nothing */
				break;
			}
		}

		new_result.coalesce ();
		result = new_result;
	}

	return result;
}
Beispiel #2
0
 // Not empty set
 inline bool
 empty() const {
     return ranges.empty();
 }