Ejemplo n.º 1
0
    vector<string> wordBreak(string s, unordered_set<string>& wordDict) {
        const int n = s.length();

        size_t max_len = 0;
        for (const auto& str: wordDict) {
            max_len = max(max_len, str.length());
        }

        vector<bool> canBreak(n + 1, false);
        vector<vector<bool>> valid(n, vector<bool>(n, false));
        canBreak[0] = true;
        for (int i = 1; i <= n; ++i) {
            for (int l = 1; l <= max_len && i - l >= 0; ++l) {
                if (canBreak[i - l] && wordDict.count(s.substr(i - l, l))) {
                    valid[i - l][i - 1] = true;
                    canBreak[i] = true;
                }
            }
        }

        vector<string> result, path;
        if (canBreak[n]) {
            wordBreakHelper(s, valid, 0, &path, &result);
        }
        return result;
    }
Ejemplo n.º 2
0
vector<string> WordBreakII::wordBreak(string s, unordered_set<string> &wordDict) {
    vector<string> result;
    vector<string> cur;
    vector<bool> canBreak(s.size() + 1, true);

    backtrack(s, wordDict, 0, cur, canBreak, result);

    return result;
}
Ejemplo n.º 3
0
    bool wordBreak(string s, unordered_set<string>& wordDict) {
        const int n = s.length();

        size_t max_len = 0;
        for (const auto& str: wordDict) {
            max_len = max(max_len, str.length());
        }

        vector<bool> canBreak(n + 1, false);
        canBreak[0] = true;
        for (int i = 1; i <= n; ++i) {
            for (int l = 1; l <= max_len && i - l >= 0; ++l) {
                if (canBreak[i - l] && wordDict.count(s.substr(i - l, l))) {
                    canBreak[i] = true;
                    break;
                }
            }
        }

        return canBreak[n];
    }
Ejemplo n.º 4
0
 vector<string> wordBreak(string s, unordered_set<string>& wordDict) {
     vector<string> result;
     string ret = "";
     if (s == "") {
         return result;
     }
     //use dp to pruning
     int len = s.length();
     vector<bool> canBreak(len + 1, false);
     canBreak[0] = true;
     for (int i = 0; i < len; i ++) {
         for (int j = i; j >= 0; j --) {
             if (wordDict.count(s.substr(j, i - j + 1)) && canBreak[j]) {
                 canBreak[i + 1] = true;
                 break;
             }
         }
     }
     if (!canBreak[len]) {
         return result;
     }
     dfs(ret, 0, s, result, wordDict);
     return result;
 }