Ejemplo n.º 1
0
Archivo: 0012.c Proyecto: jcast/euler
int main(int argc, int *argv[]) {
  int min_div_count = 500;
  int div_count     = 0;
  long triangle     = 0;
  long min_number   = 1;
  long counter      = 0;

  while(div_count <= min_div_count) {
    counter++;
    triangle  = triangle + counter;
    div_count = count_divs(triangle);
  }

  printf("%ld\n", triangle);

  return 0;
}
Ejemplo n.º 2
0
int triangle500 (int lim) {
    int i = 3;
    int res = count_divs (i) * count_divs ((i+1)/2);
    while (res <= lim) {
        i++;
        if (0 == i%2) {
            res = count_divs (i/2) * count_divs (i+1);    
        } else {
            res = count_divs (i) * count_divs ((i+1)/2);    
        }
        
    }
    return i*(i+1)/2;
}