int main(){
int cases;
scanf("%d",&cases);
while(cases){
long long a,b;
scanf("%llu %llu", &a, &b);
printf("%llu\n",gcd2(a,b) );
--cases;
}
// clock_t start,end ;
// unsigned long long a,b;
// a = 400000;
// b = 1000000000000000000;
// start = clock();
// printf("GCD of 4 and 180 is %llu \n", gcd(a,b));
// end = clock();
// double t = (double)(end-start)/CLOCKS_PER_SEC;
// printf("Elapsed: %f\n",t );
// start = clock();
// printf("GCD of 4 and 180 is %llu \n", gcd2(a,b));
// end = clock();
// t = (double)(end-start)/CLOCKS_PER_SEC;
// printf("Elapsed: %f\n",t );
return 0;
}
void gcdn(mpz_t r, mpz_t a[], size_t n)
{
size_t i;
mpz_set(r, a[0]);
for (i = 1; i < n; i++)
gcd2(r, r, a[i]); /* mpz_gcd ;-) */
}
int main () {
printf("iterative sum of squares from 1 to 10: %d\n",
summation(square, 1, 10));
printf("recursive gcd of 24 and 40: %d\n", gcd(24, 40));
printf("recursive sum of squares from 1 to 10: %d\n",
summation2(square, 1, 10));
printf("iterative gcd of 24 and 40: %d\n", gcd2(24, 40));
printf("tail-recursive gcd of 24 and 40: %d\n", gcd3(24, 40));
}
int main(void){
char word1[100] = "racecar ten";
char word2[100] = "Go hang a salami, I'm a lasagna hog";
char word3[100] = "Banana tub";
int j = 0, pal = -1;
pal = isPalindrome(word1, 0, strlen(word1));
//printf("Palindrome = %d\n", pal);
//printBinaryNum("xxxxxxxx");
j = gcd2(132, 20);
printf("Greatest common denominator = %d\n", j);
}
void ch1()
{
// 循环语句的辗除法,求两个整数的最大公约数
printf("319,377最大公约数：%d\n",gcd1(319,377)); //29
// 循环语句的辗除法,求两个整数的最大公约数
printf("319,377最大公约数：%d\n",gcd2(319,377)); //29
// 递归调用的辗除法,求两个整数的最大公约数
printf("377,319最大公约数：%d\n",gcd3(377,319)); //29
printf("319,377最大公约数：%d\n",gcd3(319,377)); //29
printf("377,319最大公约数：%d\n",gcd4(377,319)); //29
printf("319,377最大公约数：%d\n",gcd4(319,377)); //29
printf("377,319最大公约数：%d\n",gcd5(377,319)); //29
printf("319,377最大公约数：%d\n",gcd5(319,377)); //29
// 最小公倍数=两整数的乘积÷最大公约数
//printf("319,377最小公倍数：%d\n",multiple (319,377));
}
void gcd_main2(){
int a, b;
a = 128;
b = 72;
printf("%dと%dの最大公約数は%d\n", a, b, gcd2(a, b));
}
GF2m gcd(const GF2m& b1,const GF2m& b2)
{
GF2m g;
gcd2(b1.fn,b2.fn,g.fn);
return g;
}
int gcd2(int a, int b) {
if(b == 0) return a;
else return gcd2(b, a % b);
}