int trap(int A[], int n) {
vector<int> height(n, 0), presum(n, 0), right_pair_pos(n, 0);
arrayToVector(A, n, height);
calcRightPairPos(height, right_pair_pos);
calcHeightPresum(height, presum);
return getWaterTrapped(height, presum, right_pair_pos);
}
vector<int> brute_force(vector<int>& A) {
// O(N^2)
vector<int> presum(A.size() + 1, 0);
presum[0] = 0;
for (int i = 1; i <= A.size(); i++) {
if (i == 1) {
presum[i] = A[i - 1];
} else {
presum[i] = presum[i - 1] + A[i - 1];
}
}
vector<int> ans;
int biggest = INT_MIN;
for (int i = 0; i < A.size(); i++) { // [0, n - 1]
for (int j = i + 1; j <= A.size(); j++) { // [1, n]
if (biggest < presum[j] - presum[i]) {
biggest = presum[j] - presum[i];
ans.clear();
ans.push_back(i);
ans.push_back(j - 1);
}
}
}
return ans;
}
/**
* @param A an integer array
* @return A list of integers includes the index of
* the first number and the index of the last number
*/
vector<int> continuousSubarraySum(vector<int>& A) {
// Write your code here
vector<int> presum(A.size() + 1, 0);
presum[0] = 0;
for (int i = 1; i <= A.size(); i++) {
if (i == 1) {
presum[i] = A[i - 1];
} else {
presum[i] = presum[i - 1] + A[i - 1];
}
}
vector<int> ans;
int smallest_index = 0;
int biggest = INT_MIN;
for (int i = 1; i < presum.size(); i++) {
if (presum[i] - presum[smallest_index] > biggest) {
biggest = presum[i] - presum[smallest_index];
ans.clear();
ans.push_back(smallest_index);
ans.push_back(i - 1);
}
if (presum[smallest_index] > presum[i]) {
smallest_index = i;
}
}
return ans;
}
long long int Difsum(long long int x,long long int y,int d1,int d2)
{
long long int s=0;
int i;
s=s+Ordsum(x,(pow(10,d1)-1));
s=s+Ordsum(y,pow(10,d2-1));
for(i=d1+1;i<d2;i++)
s=s+presum(i);
return s;
}
/**
* @param A an integer array
* @return A list of integers includes the index of
* the first number and the index of the last number
*/
vector<int> continuousSubarraySumII(vector<int>& A) {
// Write your code here
int sum = 0;
for (auto& a : A) {
sum += a;
}
vector<int> presum(A.size() + 1, 0);
presum[0] = 0;
for (int i = 1; i <= A.size(); i++) {
if (i == 1) {
presum[i] = A[i - 1];
} else {
presum[i] = presum[i - 1] + A[i - 1];
}
}
// get largest subarray
vector<int> ans;
int smallest_index = 0;
int biggest = INT_MIN;
for (int i = 1; i < presum.size(); i++) {
if (presum[i] - presum[smallest_index] > biggest) {
biggest = presum[i] - presum[smallest_index];
ans.clear();
ans.push_back(smallest_index);
ans.push_back(i - 1);
}
if (presum[smallest_index] > presum[i]) {
smallest_index = i;
}
}
// get smallest subarray
vector<int> ans2;
int largest_index = 0;
int smallest = INT_MAX;
for (int i = 1; i < presum.size(); i++) {
if (presum[i] - presum[largest_index] < smallest) {
smallest = presum[i] - presum[largest_index];
ans2 = computeRange(largest_index, i - 1, A.size());
}
if (presum[largest_index] < presum[i]) {
largest_index = i;
}
}
if (sum == smallest) { // needs better explain
return ans;
} else {
return sum - smallest > biggest ? ans2 : ans;
}
}
int kInversePairs(int n, int k) {
vector<int> presum(1 + k);
int MOD = 1000000007;
for (int i = 1; i <= n; ++i) {
vector<int> temp(1 + k);
temp[0] = 1;
for (int j = 1; j <= k; ++j) {
int val = (presum[j] - ((j - i >= 0) ? presum[j - i] : 0) + MOD) % MOD;
temp[j] = (temp[j - 1] + val) % MOD;
}
presum = temp;
}
return (presum[k] - ((k > 0) ? presum[k - 1] : 0) + MOD) % MOD;
}
/**
* @param matrix an integer matrix
* @return the coordinate of the left-up and right-down number
*/
vector<vector<int>> submatrixSum(vector<vector<int>>& matrix) {
// Write your code here
int rows = matrix.size();
int cols = matrix[0].size();
vector<vector<int> > ans;
vector<vector<int> > presum(rows + 1, vector<int>(cols, 0));
// init presum matrix
for (int j = 0; j < cols; j++) {
for (int i = 1; i < rows + 1; i++) {
presum[i][j] = presum[i - 1][j] + matrix[i - 1][j];
}
}
for (int top = 0; top < rows + 1; top++) {
for (int down = top + 1; down < rows + 1; down++) {
vector<int> linepresum = computeLinePresum(presum, top, down);
map<int, int> exist;
int i = 0;
while (i < linepresum.size() && exist.find(linepresum[i]) == exist.end()) {
exist[linepresum[i]] = i;
i += 1;
}
if (i < linepresum.size()) {
// find it!
vector<int> p{top, exist[linepresum[i]]};
vector<int> p2{down - 1, i - 1};
ans.push_back(p);
ans.push_back(p2);
return ans;
}
}
}
return ans;
}
