Ejemplo n.º 1
0
    vector<string> wordBreak(string s, unordered_set<string>& wordDict) {
        const int n = s.length();

        size_t max_len = 0;
        for (const auto& str: wordDict) {
            max_len = max(max_len, str.length());
        }

        vector<bool> canBreak(n + 1, false);
        vector<vector<bool>> valid(n, vector<bool>(n, false));
        canBreak[0] = true;
        for (int i = 1; i <= n; ++i) {
            for (int l = 1; l <= max_len && i - l >= 0; ++l) {
                if (canBreak[i - l] && wordDict.count(s.substr(i - l, l))) {
                    valid[i - l][i - 1] = true;
                    canBreak[i] = true;
                }
            }
        }

        vector<string> result, path;
        if (canBreak[n]) {
            wordBreakHelper(s, valid, 0, &path, &result);
        }
        return result;
    }
Ejemplo n.º 2
0
 vector<string> wordBreak(string s, unordered_set<string> &dict) {
     int n = s.length();
     string t;
     vector<vector<bool>> dp(n, vector<bool>(n, false));
     int i, j;
     
     for (i = 0; i < n; i++) {
         for (j = i; j < n; j++) {
             t = s.substr(i, j-i+1);
             if (dict.find(t) != dict.end()) {
                 dp[i][j] = true;
             }
         }
     }
     
     vector<string> res;
     vector<string> path;
     wordBreakHelper(s, n-1, dp, path, res);
     return res;
 }
Ejemplo n.º 3
0
 void wordBreakHelper(const string& s, const vector<vector<bool>>& valid,
                      int start, vector<string> *path, vector<string> *result) {
     if (start == s.length()) {
         string tmp;
         for (const auto& str : *path) {
             tmp += str;
             tmp += " ";
         }
         tmp.pop_back();
         result->emplace_back(move(tmp));
         return;
     }
     for (int i = start; i < s.length(); ++i) {
         if (valid[start][i]) {
             path->emplace_back(s.substr(start, i + 1 - start));
             wordBreakHelper(s, valid, i + 1, path, result);
             path->pop_back();
         }
     }
 }
Ejemplo n.º 4
0
 // we should search the valid solution from back to front
 void wordBreakHelper(string &s, int end, vector<vector<bool>> &inDict,
                      vector<string> &path, vector<string> &res) {
     int n = s.length();
     string t;
     int i;
     if (end == -1) {
         for (i = path.size()-1; i >= 0; i--) {
             if (i != path.size()-1) {
                 t += " ";
             }
             t += path[i];
         }
         res.push_back(t);
         return;
     }
     for (i = 0; i <= end; i++) {
         if (inDict[i][end]) {
             t = s.substr(i, end-i+1);
             path.push_back(t);
             wordBreakHelper(s, i-1, inDict, path, res);
             path.pop_back();
         }
     }
 }