Ejemplo n.º 1
0
bool Polygon::DiagonalExists(int i, int j) const
{
	assume(p.size() >= 3);
	assume(i >= 0);
	assume(j >= 0);
	assume(i < (int)p.size());
	assume(j < (int)p.size());
#ifndef MATH_ENABLE_INSECURE_OPTIMIZATIONS
	if (p.size() < 3 || i < 0 || j < 0 || i >= (int)p.size() || j >= (int)p.size())
		return false;
#endif
	assume(IsPlanar());
	assume(i != j);
	if (i == j) // Degenerate if i == j.
		return false;
	if (i > j)
		Swap(i, j);
	assume(i+1 != j);
	if (i+1 == j) // Is this LineSegment an edge of this polygon?
		return false;

	Plane polygonPlane = PlaneCCW();
	LineSegment diagonal = polygonPlane.Project(LineSegment(p[i], p[j]));

	// First check that this diagonal line is not intersected by an edge of this polygon.
	for(int k = 0; k < (int)p.size(); ++k)
		if (!(k == i || k+1 == i || k == j))
			if (polygonPlane.Project(LineSegment(p[k], p[k+1])).Intersects(diagonal))
				return false;

	return IsConvex();
}
Ejemplo n.º 2
0
bool Polygon::IsSimple() const
{
	assume(IsPlanar());
	Plane plane = PlaneCCW();
	for(int i = 0; i < (int)p.size(); ++i)
	{
		LineSegment si = plane.Project(Edge(i));
		for(int j = i+2; j < (int)p.size(); ++j)
		{
			if (i == 0 && j == (int)p.size() - 1)
				continue; // These two edges are consecutive and share a vertex. Don't check that pair.
			LineSegment sj = plane.Project(Edge(j));
			if (si.Intersects(sj))
				return false;
		}
	}
	return true;
}
Ejemplo n.º 3
0
bool Polygon::Contains(const LineSegment &worldSpaceLineSegment, float polygonThickness) const
{
	if (p.size() < 3)
		return false;

	Plane plane = PlaneCCW();
	if (plane.Distance(worldSpaceLineSegment.a) > polygonThickness ||
		plane.Distance(worldSpaceLineSegment.b) > polygonThickness)
		return false;

	// For robustness, project onto the polygon plane.
	LineSegment l = plane.Project(worldSpaceLineSegment);

	if (!Contains(l.a) || !Contains(l.b))
		return false;

	for(int i = 0; i < (int)p.size(); ++i)
		if (plane.Project(Edge(i)).Intersects(l))
			return false;

	return true;
}