/**
Create an ECC shared secret between two keys
@param private_key The private ECC key
@param public_key The public key
@param out [out] Destination of the shared secret (Conforms to EC-DH from ANSI X9.63)
@param outlen [in/out] The max size and resulting size of the shared secret
@return CRYPT_OK if successful
*/
int ecc_shared_secret(ecc_key *private_key, ecc_key *public_key,
unsigned char *out, unsigned long *outlen)
{
unsigned long x;
ecc_point *result;
void *prime;
int err;
LTC_ARGCHK(private_key != NULL);
LTC_ARGCHK(public_key != NULL);
LTC_ARGCHK(out != NULL);
LTC_ARGCHK(outlen != NULL);
/* type valid? */
if (private_key->type != PK_PRIVATE) {
return CRYPT_PK_NOT_PRIVATE;
}
if (ltc_ecc_is_valid_idx(private_key->idx) == 0 || ltc_ecc_is_valid_idx(public_key->idx) == 0) {
return CRYPT_INVALID_ARG;
}
if (XSTRCMP(private_key->dp->name, public_key->dp->name) != 0) {
return CRYPT_PK_TYPE_MISMATCH;
}
/* make new point */
result = ltc_ecc_new_point();
if (result == NULL) {
return CRYPT_MEM;
}
if ((err = mp_init(&prime)) != CRYPT_OK) {
ltc_ecc_del_point(result);
return err;
}
if ((err = mp_read_radix(prime, (char *)private_key->dp->prime, 16)) != CRYPT_OK) { goto done; }
if ((err = ltc_mp.ecc_ptmul(private_key->k, &public_key->pubkey, result, prime, 1)) != CRYPT_OK) { goto done; }
x = (unsigned long)mp_unsigned_bin_size(prime);
if (*outlen < x) {
*outlen = x;
err = CRYPT_BUFFER_OVERFLOW;
goto done;
}
zeromem(out, x);
if ((err = mp_to_unsigned_bin(result->x, out + (x - mp_unsigned_bin_size(result->x)))) != CRYPT_OK) { goto done; }
err = CRYPT_OK;
*outlen = x;
done:
mp_clear(prime);
ltc_ecc_del_point(result);
return err;
}
/* crypt_get_size()
* sizeout will be the size (bytes) of the named struct or union
* return -1 if named item not found
*/
int crypt_get_size(const char* namein, unsigned int *sizeout) {
int i;
int count = sizeof(_crypt_sizes) / sizeof(_crypt_sizes[0]);
for (i=0; i<count; i++) {
if (XSTRCMP(_crypt_sizes[i].name, namein) == 0) {
*sizeout = _crypt_sizes[i].size;
return 0;
}
}
return -1;
}
/**
Find a registered hash by name
@param name The name of the hash to look for
@return >= 0 if found, -1 if not present
*/
int find_hash(const char *name)
{
int x;
LTC_ARGCHK(name != NULL);
LTC_MUTEX_LOCK(<c_hash_mutex);
for (x = 0; x < TAB_SIZE; x++) {
if (hash_descriptor[x].name != NULL && XSTRCMP(hash_descriptor[x].name, name) == 0) {
LTC_MUTEX_UNLOCK(<c_hash_mutex);
return x;
}
}
LTC_MUTEX_UNLOCK(<c_hash_mutex);
return -1;
}
/**
Find a registered cipher by name
@param name The name of the cipher to look for
@return >= 0 if found, -1 if not present
*/
int find_cipher(const char *name)
{
int x;
LTC_ARGCHK(name != NULL);
LTC_MUTEX_LOCK(<c_cipher_mutex);
for (x = 0; x < TAB_SIZE; x++) {
if (cipher_descriptor[x].name != NULL && !XSTRCMP(cipher_descriptor[x].name, name)) {
LTC_MUTEX_UNLOCK(<c_cipher_mutex);
return x;
}
}
LTC_MUTEX_UNLOCK(<c_cipher_mutex);
return -1;
}
/**
Find a registered PRNG by name
@param name The name of the PRNG to look for
@return >= 0 if found, -1 if not present
*/
int find_prng(const char *name)
{
int x;
LTC_ARGCHK(name != NULL);
LTC_MUTEX_LOCK(<c_prng_mutex);
for (x = 0; x < TAB_SIZE; x++) {
if ((prng_descriptor[x]->name != NULL) && XSTRCMP(prng_descriptor[x]->name, name) == 0) {
LTC_MUTEX_UNLOCK(<c_prng_mutex);
return x;
}
}
LTC_MUTEX_UNLOCK(<c_prng_mutex);
return -1;
}
/* XXX TODO: implement with iterators */
int rpmpsTrim(rpmps ps, rpmps filter)
{
rpmProblem *t;
rpmProblem *f;
int gotProblems = 0;
if (ps == NULL || ps->numProblems == 0)
return 0;
if (filter == NULL)
return (ps->numProblems == 0 ? 0 : 1);
t = ps->probs;
f = filter->probs;
while ((f - filter->probs) < filter->numProblems) {
if (!(*f)->ignoreProblem) {
f++;
continue;
}
while ((t - ps->probs) < ps->numProblems) {
/* LCL: looks good to me <shrug> */
if ((*f)->type == (*t)->type && (*t)->key == (*f)->key &&
XSTRCMP((*f)->str1, (*t)->str1))
break;
t++;
gotProblems = 1;
}
/* XXX This can't happen, but let's be sane in case it does. */
if ((t - ps->probs) == ps->numProblems)
break;
(*t)->ignoreProblem = (*f)->ignoreProblem;
t++, f++;
}
if ((t - ps->probs) < ps->numProblems)
gotProblems = 1;
return gotProblems;
}