int main()
{
int p, q, e, d, m, n, t, c, r;
char s;
printf("Please input the p, q: ");
scanf("%d%d", &p, &q);
n = p * q;
printf("the n is %3d\n", n);
t = (p - 1) * (q - 1);
printf("the t is %3d\n", t);
printf("Please input the e: ");
scanf("%d", &e);
if(e < 1 || e > t)
{
printf("e is error. Please input again");
scanf("%d", &e);
}
d = 1;
while(((e * d) % t) != 1)
d++;
printf("then calculate out that the d is %d\n", d);
printf("the cipher please input 1\n");
printf("the plain please input 2\n");
scanf("%d", &r);
switch(r)
{
case 1: printf("input the m: "); //输入要加密的明文数字
scanf("%d", &m);
c = candp(m, e, n);
printf("the cipher is %d\n", c);
break;
case 2: printf("input the c: ");//输入要解密的密文数字
scanf("%d", &c);
m = candp(c, d ,n);
printf("the plain is %d\n", m);
break;
}
getch();
return 0;
}
int main ( void ) {
int i, p=53, q=61;
int n = p*q;
int f = (p-1)*(q-1), e = getE(f), d = getD(e, f);
int data = 123, encry, decry;
printf("p = %d, q = %d, f = %d, e = %d, d = %d\ndata = %d\n", p, q, f, e, d, data );
encry = candp(data, e, f);
if ( encry == data ) {
printf("%s\n","cao");
}
printf("the encry is %d\n", encry);
decry = candp(encry, d, f);
printf("the decry is %d\n", decry);
}