// Give the duration of the interval between begin and end in seconds
long long int duration(const int* begin, const int* end)
{
int b[6];
int e[6];
// Fill in missing values appropriately
upperbound(begin, b);
lowerbound(end, e);
// Lowerbound both where both had -1
for (int i = 0; i < 6; ++i)
if (begin[i] == -1 && end[i] == -1)
b[i] = e[i] = (i == 1 || i == 2) ? 1 : 0;
// Find the smaller year, to use as a reference for secondsfrom
int y = b[0] < e[0] ? b[0] : e[0];
return secondsfrom(y, e) - secondsfrom(y, b);
}
vector<int> searchRange(int A[], int n, int target) {
int start = lowerbound(A, n, target);
int end = upperbound(A, n, target);
if (start != -1) {
if (A[start] != target)
start = -1;
}
if (end == -1) {
if (A[n-1] == target)
end = n-1;
} else {
if (A[end-1] == target)
end--;
else
end = -1;
}
vector<int> result(2);
result[0] = start;
result[1] = end;
return result;
}
