Exemple #1
0
int main(int argc, char** argv){
  if(argc < 3){
    printf("Usage: %s word1 word 2\n", argv[0]);
    exit(1);
  }
  printf("The distance between %s and %s is %d.\n", argv[1], argv[2], editDist(argv[1], argv[2]));

  return 0;
}
Exemple #2
0
/* Driver program */
int
main()
{
    char str1[] = "sunday";
    char str2[] = "saturday";

    int str1Length = sizeof(str1) / sizeof(str1[0]);
    int str2Length = sizeof(str2) / sizeof(str2[0]);
    memset(memo, -1 ,sizeof memo);
    int minimum = editDist(str1, str2, str1Length, str2Length);
    printf("%d\n", minimum);

    return 0;
}
Exemple #3
0
int
editDist(char str1[], char str2[], int m, int n)
{
    /*
     * If first string is empty, the only option is to
     * insert all characters of second string into first
     */
    if (m == 0) return n;

    /*
     * If second string is empty, the only option is to
     * remove all characters of first string
     */
    if (n == 0) return m;

    /* If this state has already been computed, get its value */
    if (memo[m][n] > -1) return memo[m][n];

    /*
     * If last characters of two strings are same, nothing
     * much to do. Ignore last characters and get count for
     * remaining strings.
     */
    if (str1[m-1] == str2[n-1])
        return memo[m][n] = editDist(str1, str2, m-1, n-1);

    /*
     * If last characters are not same, consider all three
     * operations on last character of first string, recursively
     * compute minimum cost for all three operations and take
     * minimum of three values.
     */
    return memo[m][n] = 1 + min ( editDist(str1, str2, m, n-1),  /* Insert  */
                                  editDist(str1, str2, m-1, n),  /* Remove  */
                                  editDist(str1, str2, m-1, n-1) /* Replace */
    );
}