static void Union(int x,int y)
{
int fx = get_father(x);
int fy = get_father(y);
int ndisx = ndis[x];
int ndisy = ndis[y];
#ifdef DBGMSG
printf("union x : %d y : %d fx : %d fy : %d\n",x+1,y+1,fx+1,fy+1);
#endif
if(fx == fy){
#ifdef DBGMSG
printf("fx == fy!return\n");
#endif
return;
}
if(rank[fx] > rank[fy]){
father[fy] = fx;
ndis[fy] = (ndisx + ndisy + 1)%2;
#ifdef DBGMSG
printf("father[%d] == %d\n",fy+1,fx+1);
printf("ndis[%d] = (ndis[%d] + ndis[%d] + 1)%2 = (%d + %d +1)%%2 = %d\n",fy+1,x+1,y+1,ndisx,ndisy,ndis[fy]);
#endif
}else{
father[fx] = fy;
if(rank[fx] == rank[fy]){
rank[fy]++;
}
ndis[fx] = (ndisx + ndisy + 1)%2;
#ifdef DBGMSG
printf("father[%d] == %d\n",fx+1,fy+1);
printf("ndis[%d] = (ndis[%d] + ndis[%d] + 1)%2 = (%d + %d +1)%%2 = %d\n",fx+1,x+1,y+1,ndisx,ndisy,ndis[fx]);
#endif
}
return;
}
int main(){
scanf("%d%d",&n,&m);
for(i=1;i<=n;i++){
scanf("%d%d",&co[i][0],&co[i][1]);
father[i]=i;
flag[i]=false;
for(j=1;j<i;j++){
edge[i][j]=false;
edge[j][i]=false;
if (judge_distance(m,i,j)){
edge[i][j]=true;
edge[j][i]=true;
}
}
}
while(scanf("%c",&c)!=EOF){
if (c=='O'){
scanf("%d",&l);
flag[l]=true;
for(i=1;i<=n;i++){
if ((flag[i])&&(edge[i][l])){
father[get_father(i)]=get_father(l);
}
}
}
if (c=='S'){
scanf("%d%d",&i,&j);
if (get_father(i)==get_father(j)){
printf("SUCCESS\n");
}
else printf("FAIL\n");
}
}
}
int main()
{
int t,n,m,c=0,i,j,k,fj,fk;
char cc;
scanf("%d",&t);
scanf("%d%d",&n,&m);
while(c<t){
#ifdef DBGMSG
printf("n -- %d\nm -- %d\n",n,m);
#endif
rank = (int*)malloc(n*sizeof(int));
father = (int*)malloc(n*sizeof(int));
ndis = (int*)malloc(n*sizeof(int));
for(i=0;i<n;i++){
make_set(i);
}
for(i=0;i<m;i++){
getchar();
scanf("%c%d%d",&cc,&j,&k);
#ifdef DBGMSG
printf("#%d : cc -- %c %d\nj -- %d\nk -- %d\n",i,cc,cc,j,k);
#endif
if((cc != 'A' && cc != 'D') || j > n || k > n){
fprintf(stderr,"invalid input\n");
exit(1);
}
if(cc == 'A'){
fj = get_father(j-1);
fk = get_father(k-1);
if(fj == fk){
if(ndis[j-1] == ndis[k-1]){
printf("In the same gang.\n");
}else{
printf("In different gangs.\n");
}
}else{
printf("Not sure yet.\n");
}
}else if(cc == 'D'){
Union(j-1,k-1);
}
}
free(rank);
free(father);
free(ndis);
if(c == (t-1)){
break;
}
scanf("%d%d",&n,&m);
}
return 0;
}
void Heap::shift_up(int pos){
//Ao chegar na raiz não faz nada
if(pos==1){
return;
}
//se o elemento for maior que o pai dele, troca de posição com o pai
else if(this->elements[pos] > this->elements[get_father(pos)]){
int temp = this->elements[pos];
this->elements[pos] = this->elements[get_father(pos)];
this->elements[get_father(pos)] = temp;
shift_up(get_father(pos));
}
}
int get_father(int x){
if (father[x]==x)
return x;
else {
int tmp=get_father(father[x]);
father[x]=tmp;
return tmp;
}
}
void traverse_up(tree_node *r, int **fdown, int **fup, int level)
{//用先序遍历树的方法遍历每个节点找出其向上的最大权值
//实际竞赛题目中，使用最简单的数组与下标来构建树，则也可以使用bfs
if(r != NULL){
get_father(r, r, fdown, fup, level, 1);
for(int i = 0; i < r->t_cnt; ++ i)
traverse_up(r->t_child[i], fdown, fup, level);
}
}
void decrease_key(position pos,element_type delta,PRIORITY_QUEUE H)
{
if(pos>H->size)
return;
position prev;
*H->elements[pos]+=delta;
for(prev=get_father(pos); prev>=1&&((*H->elements[prev])>(*H->elements[pos])); pos=prev,prev=get_father(prev)) {
swap_elements(prev,pos,H);
}
if(((*H->elements[prev])=(*H->elements[pos]))&&((*H->elements[prev])>(*H->elements[pos+1]))) {
swap_elements(prev,pos+1,H);
}
}
static int get_father(int x)
{
int prev,ndisx = ndis[x];
#ifdef DBGMSG
printf("current father of %d is %d\n",x+1,father[x]+1);
#endif
if(father[x] != x){
prev = father[x];
father[x] = get_father(father[x]);
ndis[x] = (ndisx + ndis[prev])%2;
#ifdef DBGMSG
printf("new father of %d is %d\n",x+1,father[x]+1);
printf("adjust ndis : ndis[%d] = (ndis[%d] + ndis[%d])%%2 = (%d + %d)%%2 = %d\n",x+1,x+1,prev+1,ndisx,ndis[prev],ndis[x]);
#endif
}
return father[x];
}
void get_father(tree_node *r, tree_node *p,
int **fdown, int **fup, int level, int prev = 1)
{//递归的向上求出r到达 p 祖父节点那一层的最大权值
//p指代r向上第 prev-1 层的祖父节点
//prev == 1时，p即为r自己，p->t_fa为r的父节点
//prev > level时，已经超越了向上的最大层数level
//递归终止条件
//若p的父节点为空指针，即p已经为根节点
if(p->t_fa == NULL)
return;
//prev > level是递归结束条件
if(prev > level)
return;
if(prev == level){
//到达最高的祖父节点时，不访问孩子子树
fup[r->t_idx][prev] = p->t_fa->t_value;
}
else{
//其他祖父节点可以到达其孩子子树
for(int i = 0; i < p->t_fa->t_cnt; ++ i)
//遍历p点的父节点的所有孩子节点，除过自己
//即遍历p点的所有兄弟节点
if(p->t_fa->t_child[i] != p){
//累加父节点的向下权值时要除去p自己这一子树的分支
//r节点向上prev层的最大权值等于
//上面prev层的祖父节点的所有孩子节点的向下 level-prev-1 层的最大权值
//再加上孩子节点自己的权值
fup[r->t_idx][prev] +=
fdown[p->t_fa->t_child[i]->t_idx][level - prev - 1];
fup[r->t_idx][prev] += p->t_fa->t_child[i]->t_value;
}
//还要加上p的父节点的权值
fup[r->t_idx][prev] += p->t_fa->t_value;
}
//递归上一层父节点
get_father(r, p->t_fa, fdown, fup, level, prev + 1);
}