int main()
{
char s[1024];
int wins=0;
FILE *f = fopen("poker.txt", "rb");
if ( !f ) { perror("poker.txt"); return 1; }
while ( fgets(s, 1023, f) != NULL ) {
hand h1, h2;
int n = read(h1, s);
read(h2, s+n+1);
if ( p1_wins(h1, h2) ) {
printf("p1 wins ");
++wins;
} else
printf(" ");
printf("p1=(");
print(h1);
score s1 = getscore(h1);
printf(") %s (%d) -- ", rankstr(s1.rank), s1.topcard.value);
printf("p2=(");
print(h2);
score s2 = getscore(h2);
printf(") %s (%d)\n", rankstr(s2.rank), s2.topcard.value);
}
printf("p1 wins: %d\n", wins);
}
int p1_wins(hand p1, hand p2)
{
score l = getscore(p1);
score r = getscore(p2);
if ( l.rank == r.rank ) {
if ( l.topcard.value > r.topcard.value )
return 1;
return 0;
}
return l.rank > r.rank;
}
void WinScreen::draw(){
background();
ofSetColor(250, 200);
font.drawString("Congratulations you beat all the levels", ofGetWidth()*0.2, ofGetHeight()*0.3);
font.drawString("Total Score: "+ ofToString(getscore()) , ofGetWidth()*0.4, ofGetWindowHeight()*0.5);
if(button(0.5,0.8, "Main Menu"))
{
State::setState(MM);//sends you to the next gamestate
//State::gameStates[LVL1].get()->resetLevel();
}
}
/**************************
** bench_with_confidence **
***************************
** Given a benchmark id that indicates a function, this routine
** repeatedly calls that benchmark, seeking to collect and replace
** scores to get 5 that meet the confidence criteria.
**
** The above is mathematically questionable, as the statistical theory
** depends on independent observations, and if we exchange data points
** depending on what we already have then this certainly violates
** independence of the observations. Hence I changed this so that at
** most 30 observations are done, but none are deleted as we go
** along. We simply do more runs and hope to get a big enough sample
** size so that things stabilize. Uwe F. Mayer
**
** Return 0 if ok, -1 if failure. Returns mean
** and std. deviation of results if successful.
*/
static int bench_with_confidence(int fid, /* Function id */
double *mean, /* Mean of scores */
double *stdev, /* Standard deviation */
ulong *numtries) /* # of attempts */
{
double myscores[30]; /* Need at least 5 scores, use at most 30 */
double c_half_interval; /* Confidence half interval */
int i; /* Index */
/* double newscore; */ /* For improving confidence interval */
/*
** Get first 5 scores. Then begin confidence testing.
*/
for (i=0;i<5;i++)
{ (*funcpointer[fid])();
myscores[i]=getscore(fid);
#ifdef DEBUG
printf("score # %d = %g\n", i, myscores[i]);
#endif
}
*numtries=5; /* Show 5 attempts */
/*
** The system allows a maximum of 30 tries before it gives
** up. Since we've done 5 already, we'll allow 25 more.
*/
/*
** Enter loop to test for confidence criteria.
*/
while(1)
{
/*
** Calculate confidence. Should always return 0.
*/
if (0!=calc_confidence(myscores,
*numtries,
&c_half_interval,
mean,
stdev)) return(-1);
/*
** Is the length of the half interval 5% or less of mean?
** If so, we can go home. Otherwise, we have to continue.
*/
if(c_half_interval/ (*mean) <= (double)0.05)
break;
#ifdef OLDCODE
#undef OLDCODE
#endif
#ifdef OLDCODE
/* this code is no longer valid, we now do not replace but add new scores */
/* Uwe F. Mayer */
/*
** Go get a new score and see if it
** improves existing scores.
*/
do {
if(*numtries==10)
return(-1);
(*funcpointer[fid])();
*numtries+=1;
newscore=getscore(fid);
} while(seek_confidence(myscores,&newscore,
&c_half_interval,mean,stdev)==0);
#endif
/* We now simply add a new test run and hope that the runs
finally stabilize, Uwe F. Mayer */
if(*numtries==30) return(-1);
(*funcpointer[fid])();
myscores[*numtries]=getscore(fid);
#ifdef DEBUG
printf("score # %ld = %g\n", *numtries, myscores[*numtries]);
#endif
*numtries+=1;
}
return(0);
}
/**************************
** bench_with_confidence **
***************************
** Given a benchmark id that indicates a function, this
** routine repeatedly calls that benchmark, seeking
** to collect enough scores to get 5 that meet the confidence
** criteria. Return 0 if ok, -1 if failure.
** Returns mean ans std. deviation of results if successful.
*/
static int bench_with_confidence(int fid, /* Function id */
double *mean, /* Mean of scores */
double *stdev, /* Standard deviation */
ulong *numtries) /* # of attempts */
{
double myscores[5]; /* Need at least 5 scores */
double c_half_interval; /* Confidence half interval */
int i; /* Index */
double newscore; /* For improving confidence interval */
/*
** Get first 5 scores. Then begin confidence testing.
*/
TotalTime = (double)0.0;
for (i=0;i<5;i++)
{ (*funcpointer[fid])();
myscores[i]=getscore(fid);
TotalTime += CurrTime;
}
*numtries=5; /* Show 5 attempts */
/*
** The system allows a maximum of 10 tries before it gives
** up. Since we've done 5 already, we'll allow 5 more.
*/
/*
** Enter loop to test for confidence criteria.
*/
while(1)
{
/*
** Calculate confidence.
*/
calc_confidence(myscores,
&c_half_interval,
mean,
stdev);
/*
** Is half interval 5% or less of mean?
** If so, we can go home. Otherwise,
** we have to continue.
*/
if(c_half_interval/ (*mean) <= (double)0.05)
break;
/*
** Go get a new score and see if it
** improves existing scores.
*/
do {
if(*numtries==10)
return(-1);
(*funcpointer[fid])();
*numtries+=1;
newscore=getscore(fid);
} while(seek_confidence(myscores,&newscore,
&c_half_interval,mean,stdev)==0);
}
return(0);
}
void tkd_exec(){
int i,j,k,s,t,tau;
miss = 0;
/*
* calculate missing values O(N*D) and initialize T
*/
for(i = 0; i < N; ++i){
for(j = 0; j < D; ++j){
dataset[i].T[j] = N-1;//initialization
miss += dataset[i].missing[j];
}
}
/*
* calculate the number of objects a certain object dominates on a certain dimention O(D*N*logN)
*/
for(i = 0; i < D; ++i){
missd[i] = 0;
for(j = 0; j < N; ++j){
arr[j] = j;
if(dataset[j].missing[i])
++missd[i];
}
quicksort(arr,i,0,N-1);
j = N-1;
while(j>=missd[i]){
k = j;
while(k>0 && dataset[arr[j]].value[i]==dataset[arr[--k]].value[i]);
if(k==0)
--k;
for(s = k+1; s <= j; ++s)
dataset[arr[s]].T[i] = missd[i]+N-k-2;
j = k;
}
}
/*
* calculate maxscore O(N*D)
*/
for(i = 0;i < N; ++i){
maxscore[i]=dataset[i].T[0];
for(j = 1; j < D; ++j)
if(dataset[i].T[j]<maxscore[i])
maxscore[i]=dataset[i].T[j];
}
/*
* maintain a priority queue O(N*logN)
*/
queue[0] = N;
for(i = 1;i <= N; ++i)
queue[i] = i-1;
for(i = 1; i <= N/2; ++i)
perculateUp(maxscore,queue,i);
/*
* maintain a candidate set with max scores and using pruning
*/
tau = -1,candidateset[0]=0;
while(queue[0]){
t = popqueue(queue,maxscore);
if(maxscore[t]<tau) // maxscore pruning
break;
else{
score[t]=getscore(t,tau,miss,candidateset[0]); // bitscore pruning
if(score[t]>tau || tau<0){
if(candidateset[0]==K){
for(i=1;i<=candidateset[0];++i){
if(score[candidateset[i]]==tau){
candidateset[i]=t;
break;
}
}
}
else {
candidateset[++candidateset[0]]=t;
}
if(candidateset[0]==K){ // candidate set full
tau=score[candidateset[1]];
for(i=2;i<=K;++i)
if(score[candidateset[i]]<tau)
tau=score[candidateset[i]];
}
}
}
}
}