PyObject*
_Py_bytes_isdigit(const char *cptr, Py_ssize_t len)
{
register const unsigned char *p
= (unsigned char *) cptr;
register const unsigned char *e;
/* Shortcut for single character strings */
if (len == 1 && Py_ISDIGIT(*p))
Py_RETURN_TRUE;
/* Special case for empty strings */
if (len == 0)
Py_RETURN_FALSE;
e = p + len;
for (; p < e; p++) {
if (!Py_ISDIGIT(*p))
Py_RETURN_FALSE;
}
Py_RETURN_TRUE;
}
/* Given a number of the form:
digits[remainder]
where ptr points to the start and end points to the end, find where
the integer part ends. This could be a decimal, an exponent, both,
or neither.
If a decimal point is present, set *has_decimal and increment
remainder beyond it.
Results are undefined (but shouldn't crash) for improperly
formatted strings.
*/
static void
parse_number(PyObject *s, Py_ssize_t pos, Py_ssize_t end,
Py_ssize_t *n_remainder, int *has_decimal)
{
Py_ssize_t remainder;
while (pos<end && Py_ISDIGIT(PyUnicode_READ_CHAR(s, pos)))
++pos;
remainder = pos;
/* Does remainder start with a decimal point? */
*has_decimal = pos<end && PyUnicode_READ_CHAR(s, remainder) == '.';
/* Skip the decimal point. */
if (*has_decimal)
remainder++;
*n_remainder = end - remainder;
}
