int main()
{
char *str=NULL; //测试点1
ReplaceBlank(str,1);
printf("%s\n",str);
char str1[50]={"We are happy"}; //测试点2
ReplaceBlank(str1,50);
printf("%s\n",str1);
char str2[50]={"Changzhiwei"}; //测试点3
ReplaceBlank(str2,50);
printf("%s\n",str2);
return 0;
}
int main(int argc, const char * argv[]) {
char string[40] = "we are happy.";
ReplaceBlank(string, 40);
std::cout<< "" <<std::endl;
return 0;
}
int main()
{
//虽然AC了（主要九度的测试用例没有大于这个范围的），但是人为地限制str的长度并不是最佳的方法，
//最好使用C++中的string类或java中的String类，
//但目前在C语言中，我还不知道怎么可以不限定长度地从键盘接受输入的字符串。
static char str[10000000];
gets(str);
char *dest = ReplaceBlank(str);
if(dest != NULL)
puts(dest);
free(dest);
dest = NULL;
return 0;
}
// ====================测试代码====================
void Test(char* testName, char str[], int length, char expected[])
{
if(testName != nullptr)
printf("%s begins: ", testName);
ReplaceBlank(str, length);
if(expected == nullptr && str == nullptr)
printf("passed.\n");
else if(expected == nullptr && str != nullptr)
printf("failed.\n");
else if(strcmp(str, expected) == 0)
printf("passed.\n");
else
printf("failed.\n");
}
void Test(char* testName, char string[], int length, char expected[])
{
if(testName != NULL)
printf("%s begins: ", testName);
ReplaceBlank(string, length);
if(expected == NULL && string == NULL)
printf("passed.\n");
else if(expected == NULL && string != NULL)
printf("failed.\n");
else if(strcmp(string, expected) == 0)
printf("passed.\n");
else
printf("failed.\n");
}
int main() {
char string[] = "li jun giuang";
ReplaceBlank(string,100);
return 0;
}
