Esempio n. 1
0
static inline int minimumYearForDST()
{
    // Because of the 2038 issue (see maximumYearForDST) if the current year is
    // greater than the max year minus 27 (2010), we want to use the max year
    // minus 27 instead, to ensure there is a range of 28 years that all years
    // can map to.
    return std::min(msToYear(jsCurrentTime()), maximumYearForDST() - 27) ;
}
Esempio n. 2
0
/*
 * Find an equivalent year for the one given, where equivalence is deterined by
 * the two years having the same leapness and the first day of the year, falling
 * on the same day of the week.
 *
 * This function returns a year between this current year and 2037, however this
 * function will potentially return incorrect results if the current year is after
 * 2010, (rdar://problem/5052975), if the year passed in is before 1900 or after
 * 2100, (rdar://problem/5055038).
 */
int equivalentYearForDST(int year)
{
    static int minYear = mimimumYearForDST();
    static int maxYear = maximumYearForDST();
    
    int difference;
    if (year > maxYear)
        difference = minYear - year;
    else if (year < minYear)
        difference = maxYear - year;
    else
        return year;

    int quotient = difference / 28;
    int product = (quotient) * 28;

    year += product;
    ASSERT((year >= minYear && year <= maxYear) || (product - year == static_cast<int>(NaN)));
    return year;
}
Esempio n. 3
0
/*
 * Find an equivalent year for the one given, where equivalence is deterined by
 * the two years having the same leapness and the first day of the year, falling
 * on the same day of the week.
 *
 * This function returns a year between this current year and 2037, however this
 * function will potentially return incorrect results if the current year is after
 * 2010, (rdar://problem/5052975), if the year passed in is before 1900 or after
 * 2100, (rdar://problem/5055038).
 */
int equivalentYearForDST(int year)
{
    // It is ok if the cached year is not the current year as long as the rules
    // for DST did not change between the two years; if they did the app would need
    // to be restarted.
    static int minYear = minimumYearForDST();
    int maxYear = maximumYearForDST();

    int difference;
    if (year > maxYear)
        difference = minYear - year;
    else if (year < minYear)
        difference = maxYear - year;
    else
        return year;

    int quotient = difference / 28;
    int product = (quotient) * 28;

    year += product;
    return year;
}
/*
 * Find an equivalent year for the one given, where equivalence is deterined by
 * the two years having the same leapness and the first day of the year, falling
 * on the same day of the week.
 *
 * This function returns a year between this current year and 2037, however this
 * function will potentially return incorrect results if the current year is after
 * 2010, (rdar://problem/5052975), if the year passed in is before 1900 or after
 * 2100, (rdar://problem/5055038).
 */
int equivalentYearForDST(int year)
{
    // It is ok if the cached year is not the current year as long as the rules
    // for DST did not change between the two years; if they did the app would need
    // to be restarted.
    static int minYear = minimumYearForDST();
    int maxYear = maximumYearForDST();

    int difference;
    if (year > maxYear)
        difference = minYear - year;
    else if (year < minYear)
        difference = maxYear - year;
    else
        return year;

    int quotient = difference / 28;
    int product = (quotient) * 28;

    year += product;
    ASSERT((year >= minYear && year <= maxYear) || (product - year == static_cast<int>(std::numeric_limits<double>::quiet_NaN())));
    return year;
}