Esempio n. 1
0
DStr& DStr::operator+=(const DStr& other)
{
    if (!other.text_) return *this;
    nadd(other.text_, other.byteLength_);
    DynBlockItem *b;
    for (b = other.blocks.first; b; b = b -> next)
        nadd(b -> data, b -> byteCount);
    return *this;
}
Esempio n. 2
0
double newton(int N, double *Nt, double *x, double *y){
	int i;
	double iks[N];
	for(i = 0; i < N; i++){
		Nt[i] = 0;
		iks[i] = 0;
	}
	iks[0] = 1;
	Nt[0] = y[0];
	double ai;

	for(i = 1; i < N; i++){
		int j;
		for(j = N-1; j > 0; j--){
			iks[j] += iks[j-1];
			iks[j-1] *= -x[i-1];
		}
		ai = (y[i] - Polynomial(N, Nt, x[i]))/(Polynomial(N, iks, x[i]));
		// printf("ai: %f, y[i] = %f, rmian = %f, Licznik = %f\n", ai, y[i], Polynomial(N, Nt, x[i]), Polynomial(N, iks, x[i]));
		// for(j = 0; j < N; j++){
		// 	printf("j: %i, iks: %f, Nt: %f \n", j, iks[j], Nt[j]);
		// }
		nadd(N, Nt, iks, ai);
	}
	// int j;
	// for(j = 0; j < N; j++){
	// 		printf("j: %i, iks: %f, Nt: %f \n", j, iks[j], Nt[j]);
	// 	}
	return 0;
}
Esempio n. 3
0
DStr& DStr::operator+= (const Str& addingStr)
{
    nadd((char*) addingStr, addingStr.length());
    return *this;
}
Esempio n. 4
0
DStr& DStr::operator+= (const char *adding)
{
    if (!text_ || *adding)
        nadd(adding, strlen(adding));
    return *this;
}