bool DominatorTree::dominates(const BasicBlockEdge &BBE,
const BasicBlock *UseBB) const {
// If the BB the edge ends in doesn't dominate the use BB, then the
// edge also doesn't.
const BasicBlock *Start = BBE.getStart();
const BasicBlock *End = BBE.getEnd();
if (!dominates(End, UseBB))
return false;
// Simple case: if the end BB has a single predecessor, the fact that it
// dominates the use block implies that the edge also does.
if (End->getSinglePredecessor())
return true;
// The normal edge from the invoke is critical. Conceptually, what we would
// like to do is split it and check if the new block dominates the use.
// With X being the new block, the graph would look like:
//
// DefBB
// /\ . .
// / \ . .
// / \ . .
// / \ | |
// A X B C
// | \ | /
// . \|/
// . NormalDest
// .
//
// Given the definition of dominance, NormalDest is dominated by X iff X
// dominates all of NormalDest's predecessors (X, B, C in the example). X
// trivially dominates itself, so we only have to find if it dominates the
// other predecessors. Since the only way out of X is via NormalDest, X can
// only properly dominate a node if NormalDest dominates that node too.
int IsDuplicateEdge = 0;
for (const_pred_iterator PI = pred_begin(End), E = pred_end(End);
PI != E; ++PI) {
const BasicBlock *BB = *PI;
if (BB == Start) {
// If there are multiple edges between Start and End, by definition they
// can't dominate anything.
if (IsDuplicateEdge++)
return false;
continue;
}
if (!dominates(End, BB))
return false;
}
return true;
}
bool DominatorTree::dominates(const BasicBlockEdge &BBE,
const BasicBlock *UseBB) const {
// Assert that we have a single edge. We could handle them by simply
// returning false, but since isSingleEdge is linear on the number of
// edges, the callers can normally handle them more efficiently.
assert(BBE.isSingleEdge());
// If the BB the edge ends in doesn't dominate the use BB, then the
// edge also doesn't.
const BasicBlock *Start = BBE.getStart();
const BasicBlock *End = BBE.getEnd();
if (!dominates(End, UseBB))
return false;
// Simple case: if the end BB has a single predecessor, the fact that it
// dominates the use block implies that the edge also does.
if (End->getSinglePredecessor())
return true;
// The normal edge from the invoke is critical. Conceptually, what we would
// like to do is split it and check if the new block dominates the use.
// With X being the new block, the graph would look like:
//
// DefBB
// /\ . .
// / \ . .
// / \ . .
// / \ | |
// A X B C
// | \ | /
// . \|/
// . NormalDest
// .
//
// Given the definition of dominance, NormalDest is dominated by X iff X
// dominates all of NormalDest's predecessors (X, B, C in the example). X
// trivially dominates itself, so we only have to find if it dominates the
// other predecessors. Since the only way out of X is via NormalDest, X can
// only properly dominate a node if NormalDest dominates that node too.
for (const_pred_iterator PI = pred_begin(End), E = pred_end(End);
PI != E; ++PI) {
const BasicBlock *BB = *PI;
if (BB == Start)
continue;
if (!dominates(End, BB))
return false;
}
return true;
}
bool DominatorTree::dominates(const BasicBlockEdge &BBE, const Use &U) const {
Instruction *UserInst = cast<Instruction>(U.getUser());
// A PHI in the end of the edge is dominated by it.
PHINode *PN = dyn_cast<PHINode>(UserInst);
if (PN && PN->getParent() == BBE.getEnd() &&
PN->getIncomingBlock(U) == BBE.getStart())
return true;
// Otherwise use the edge-dominates-block query, which
// handles the crazy critical edge cases properly.
const BasicBlock *UseBB;
if (PN)
UseBB = PN->getIncomingBlock(U);
else
UseBB = UserInst->getParent();
return dominates(BBE, UseBB);
}
bool DominatorTree::dominates(const BasicBlockEdge &BBE, const Use &U) const {
// Assert that we have a single edge. We could handle them by simply
// returning false, but since isSingleEdge is linear on the number of
// edges, the callers can normally handle them more efficiently.
assert(BBE.isSingleEdge());
Instruction *UserInst = cast<Instruction>(U.getUser());
// A PHI in the end of the edge is dominated by it.
PHINode *PN = dyn_cast<PHINode>(UserInst);
if (PN && PN->getParent() == BBE.getEnd() &&
PN->getIncomingBlock(U) == BBE.getStart())
return true;
// Otherwise use the edge-dominates-block query, which
// handles the crazy critical edge cases properly.
const BasicBlock *UseBB;
if (PN)
UseBB = PN->getIncomingBlock(U);
else
UseBB = UserInst->getParent();
return dominates(BBE, UseBB);
}