void IntervalSet::add(const Interval &addition) {
if (_readonly) {
throw IllegalStateException("can't alter read only IntervalSet");
}
if (addition.b < addition.a) {
return;
}
// find position in list
for (auto iterator = _intervals.begin(); iterator != _intervals.end(); ++iterator) {
Interval r = *iterator;
if (addition == r) {
return;
}
if (addition.adjacent(r) || !addition.disjoint(r)) {
// next to each other, make a single larger interval
Interval bigger = addition.Union(r);
*iterator = bigger;
// make sure we didn't just create an interval that
// should be merged with next interval in list
while (iterator + 1 != _intervals.end()) {
Interval next = *++iterator;
if (!bigger.adjacent(next) && bigger.disjoint(next)) {
break;
}
// if we bump up against or overlap next, merge
iterator = _intervals.erase(iterator);// remove this one
--iterator; // move backwards to what we just set
*iterator = bigger.Union(next); // set to 3 merged ones
// ml: no need to advance iterator, we do that in the next round anyway. ++iterator; // first call to next after previous duplicates the result
}
return;
}
if (addition.startsBeforeDisjoint(r)) {
// insert before r
//--iterator;
_intervals.insert(iterator, addition);
return;
}
// if disjoint and after r, a future iteration will handle it
}
// ok, must be after last interval (and disjoint from last interval)
// just add it
_intervals.push_back(addition);
}
IntervalSet IntervalSet::And(const IntervalSet &other) const {
IntervalSet intersection;
size_t i = 0;
size_t j = 0;
// iterate down both interval lists looking for nondisjoint intervals
while (i < _intervals.size() && j < other._intervals.size()) {
Interval mine = _intervals[i];
Interval theirs = other._intervals[j];
if (mine.startsBeforeDisjoint(theirs)) {
// move this iterator looking for interval that might overlap
i++;
} else if (theirs.startsBeforeDisjoint(mine)) {
// move other iterator looking for interval that might overlap
j++;
} else if (mine.properlyContains(theirs)) {
// overlap, add intersection, get next theirs
intersection.add(mine.intersection(theirs));
j++;
} else if (theirs.properlyContains(mine)) {
// overlap, add intersection, get next mine
intersection.add(mine.intersection(theirs));
i++;
} else if (!mine.disjoint(theirs)) {
// overlap, add intersection
intersection.add(mine.intersection(theirs));
// Move the iterator of lower range [a..b], but not
// the upper range as it may contain elements that will collide
// with the next iterator. So, if mine=[0..115] and
// theirs=[115..200], then intersection is 115 and move mine
// but not theirs as theirs may collide with the next range
// in thisIter.
// move both iterators to next ranges
if (mine.startsAfterNonDisjoint(theirs)) {
j++;
} else if (theirs.startsAfterNonDisjoint(mine)) {
i++;
}
}
}
return intersection;
}