/*******************************************************
* Que 1. Discuss how stacks can be used for balancing
* of symbols
*
* Parameters : Expression (char array)
* size of array
* returns : bool (true/false)
*******************************************************/
bool IsExpressionBalanced(char A[], int size)
{
LinkedListStack stack;
printf("Expression : %s\n",A);
int i;
char a,temp;
for(i=0;i<size;i++)
{
a = A[i];
switch(a)
{
case '(': case '{': case '[':
stack.Push(a);
break;
case ')': case '}' : case ']':
temp = stack.Pop();
if(temp == -1)
return false;
else
{
if((temp == '(' && a != ')') ||
(temp == '{' && a != '}') ||
(temp == '[' && a != ']')
)
return false;
}
break;
}
}
if(stack.Pop() != -1)
return false;
else
return true;
} /* END QUE 1 */
/*************************************************************
* Que 6. Reverse stack element using recursion. without using
* Another stack.
*
* Comment :
*
* Parameters : Stack
* Returns : None
*************************************************************/
void ReveseStack(LinkedListStack &stack)
{
if(stack.IsEmpty())
return;
int data = stack.Pop();
ReveseStack(stack);
AddElementAtBottom(stack,data);
}
void AddElementAtBottom(LinkedListStack &stack, int data)
{
if(stack.IsEmpty())
{
stack.Push(data);
return;
}
int temp = stack.Pop();
AddElementAtBottom(stack,data);
stack.Push(temp);
}
int main(){
LinkedListStack<int> stack = LinkedListStack<int>();
stack.push(1);
stack.push(2);
stack.push(3);
stack.push(4);
stack.push(5);
stack.push(6);
stack.push(7);
Invierte(stack, 3);
return 0;
}
void Invierte(LinkedListStack <T> stack, const int &positions){ //tengo que poner el type aqui ya????? Se puede hacer con listas??
T *intermedia = new T[positions];
int i = 0;
while (!stack.empty() && i<positions){
intermedia[i] = stack.top();
stack.pop();
i++;
}
for (int j = 0 ; j <i; j++){
stack.push(intermedia[j]);
}
delete[] intermedia;
}
/***************************************************************
* Que 7. Given an array A, the apan S[i] of A[i] is the
* maximum number of consecutive elements A[j]
* elements A[j] and such that A[j] <= A[i]
*
* Commenst :
*
* Parameters : integer arrays.
* Retuns : longest spans
*
**************************************************************/
int *FindingSpans(int A[],int size)
{
LinkedListStack stack;
int p;
int * s = new int[size];
for(int i=0;i<size;i++)
{
while(!stack.IsEmpty())
{
if(A[i] > A[stack.Top()])
stack.Pop();
else
break;
}
if(stack.IsEmpty())
p = -1;
else
p = stack.Top();
s[i] = i-p;
stack.Push(i);
}
return s;
}
/*************************************************************
* Que 3. Post fix expression evaluation
*
* Comment : 1) prepare stack for holding operands only.
* 2) Push when numbers are read.
* 3) Pop two numbers when ever operand is encountered.
*
* Parameters : expression array
* Returns : int (eval result)
*************************************************************/
int PostFixEval(char A[])
{
LinkedListStack stack;
int tokenType = EMPTY,num,i=0;;
char token;
while((tokenType = ReadToken(A,i,token,num)) != EMPTY)
{
if(tokenType == OPERAND) //Numbers
{
stack.Push(token - '0');
}
else if(tokenType == OPERATOR) //Mathematical operator
{
int A = stack.Pop();
int B = stack.Pop();
stack.Push(Operate(A,B,token));
}
else
{
//Should not reach here
assert(1 == 0);
}
}
if(stack.IsEmpty())
return -1;
return stack.Pop();
}
// Test input:
// to be or not to - be - - that - - - is
// run with: cat data/tobe.txt | ./bin/stack
int main(int argc, char *argv[])
{
LinkedListStack<std::string> stackList;
ResizingArrayStack<std::string> stackArray;
string lineInput;
while (cin >> lineInput)
{
string *item = new string(lineInput);
if(item->compare("-"))
{
stackList.push(item);
stackArray.push(item);
}
else if(!stackList.isEmpty())
{
cout << *stackList.pop() << " ";
cout << *stackArray.pop() << " ";
}
}
cout << endl << "(" << stackList.size() << " left on stackList)" << endl;
cout << "(" << stackArray.size() << " left on stackArray)" << endl;
return 0;
}
/*************************************************************
* Que 5. Use stack to find minimum element for all stack
* elements
*
* Comment : Creating min stack to get current index minimum
* Element for all elements.
*
* 1. Improved space complexity by pushing in stack
* Only if there is more less value available &
* and popped only when the current stack top value
* is equal to array value.
*
* Parameters : integer array
* Retuns : None
**************************************************************/
void GetMinimum(int A[],int size)
{
if(size == 0) return;
LinkedListStack stack;
stack.Push(A[0]);
for(int i=1; i<size; i++)
{
if(stack.Top() > A[i])
stack.Push(A[i]);
//else
//stack.Push(stack.Top());
}
for(int i=size - 1;i>=0;i--)
printf("%d ",A[i]);
printf("\n");
int c = stack.GetSize();
for(int i=0;i<c;i++)
printf("%d ",stack.Pop());
printf("\n");
}
/*******************************************************
* Que 2. Infix to Postfix conversion.
*
* Parameters : Expression
* Retuns : None
*
* Time Complexity : O(N)
*******************************************************/
char * InfixToPostFix(char A[])
{
LinkedListStack stack;
char * output = new char[1024];
int iOutput = 0;
int tokenType = EMPTY;
int i=0,num;
char token;
char topStack = '\0';
while((tokenType = ReadToken(A,i,token,num)) != EMPTY)
{
if(tokenType == OPERAND) //Numbers
{
//Add simply in output string
output[iOutput++] = token; //num - '0';
}
else if(tokenType == OPERATOR) //Mathematical operator
{
if(!stack.IsEmpty()) topStack = stack.Top();
else topStack = '\0';
if(topStack == '\0' || topStack == '(' ||
topStack == '{' || topStack == '[')
{
stack.Push(token);
}
else
{
if(CompairPrecedence(topStack,token))
stack.Push(token);
else
{
while( topStack != -1 && !CompairPrecedence(topStack,token) &&
topStack != '\0' &&
topStack != '(' &&
topStack != '{' &&
topStack != '[')
{
output[iOutput++] = stack.Pop();
topStack = stack.Top();
}
stack.Push(token);
}
}
}
else if(tokenType == RIGHTP) //Right parenthesis
{
char top = stack.Top();
while(top != '(' ) //&& topStack != '{' && topStack != '[')
{
output[iOutput++] = stack.Pop();
top = stack.Top();
}
stack.Pop();
}
else if(tokenType == LEFTP) //Left parenthesis
{
stack.Push(token);
}
}
while(!stack.IsEmpty())
output[iOutput++] = stack.Pop();
output[iOutput] = '\0';
return output;
}
