tree
current_nonlambda_scope (void)
{
tree scope = current_scope ();
for (;;)
{
if (TREE_CODE (scope) == FUNCTION_DECL
&& LAMBDA_FUNCTION_P (scope))
{
scope = CP_TYPE_CONTEXT (DECL_CONTEXT (scope));
continue;
}
else if (LAMBDA_TYPE_P (scope))
{
scope = CP_TYPE_CONTEXT (scope);
continue;
}
break;
}
return scope;
}
const NamespaceTree TypeTree::fullyQualifiedNamespace() const
{
/* std::list<tree> namespaceNodes;
// For types, we have to start with the CP_TYPE_CONTEXT, and then move over to the CP_DECL_CONTEXT
// as we iterate over the nested contexts. Also, namespaces can be aliased, make sure we have the original.
tree& startingScope = ORIGINAL_NAMESPACE( CP_TYPE_CONTEXT( m_tree ));
// If this is the global namespace, return the scope resolution operator
if( startingScope == global_namespace )
{
namespaceNodes.push_back( global_namespace );
}
else
{
// We have to build out the full namespace context by context
for( tree& currentScope = startingScope; currentScope != global_namespace; currentScope = ORIGINAL_NAMESPACE( CP_DECL_CONTEXT( currentScope ) ))
{
// We might be inside of a class or struct. If so, that is the current scope level name.
if( TREE_CODE( currentScope ) == RECORD_TYPE )
{
namespaceNodes.push_front( TYPE_NAME( currentScope ) );
}
else
{
namespaceNodes.push_front( currentScope );
}
}
}
// Return the full scope
return( namespaceNodes );
*/
return( NamespaceTree( ORIGINAL_NAMESPACE( CP_TYPE_CONTEXT( m_tree )) ) );
}
