コード例 #1
0
ファイル: problem23.c プロジェクト: sggrissom/project-euler
internal void
PopulateAbundantNumberList()
{
    u32 *List = 0;
    
    for(u32 PotentialAbundantNumber = 1;
        PotentialAbundantNumber < AbundantNumberLimit;
        ++PotentialAbundantNumber)
    {
        if(IsAbundant(PotentialAbundantNumber))
        {
            buffer_push(List, PotentialAbundantNumber);
        }
    }

    AbundantNumberList.List = List;
    AbundantNumberList.Length = buffer_count(List);
}
コード例 #2
0
int _tmain(int argc, _TCHAR* argv[])
{
	const int max = 28123;
	std::vector<int> abudantNumbers;
	std::set<int> result;
	
	

	for (int i = 2; i <= max; ++i)
	{
		if (IsAbundant(i))
		{
			abudantNumbers.push_back(i);
		}
	}

	
	std::set<int>::size_type numberOfAbundantNumbers = abudantNumbers.size();

	for (int i = 2; i <= max; ++i)
	{
		if ((i % 2 == 0) && IsAbundant(i / 2))
		{
			//std::cout << i << " = " << i / 2 << " + " << i / 2 << std::endl;
			continue;
		}
		else
		{
			result.insert(i);
			for (std::set<int>::size_type j = 0; j < abudantNumbers.size(); ++j)
			{
				int first = abudantNumbers[j];
				int second = i - first;

				if (second < abudantNumbers[0])
				{
					// concluded: CANNOT be expressed as sum of two abudant numbers
					break; 
				}
				if (second <= abudantNumbers[numberOfAbundantNumbers - 1])
				{
					if (std::find(abudantNumbers.begin(), abudantNumbers.end(), second) != abudantNumbers.end())
					{
						// concluded: CAN be expressed as sum of two abudant numbers
						//std::cout << i << " = " << first << " + " << second << std::endl;			
						result.erase(i);
						break;
					}
				}

			}
		}
	}

	int sum = 0;
	for (const auto& element : result)	
		sum += element;	

	std::cout << sum << std::endl;

	return 0;
}