コード例 #1
0
ファイル: krtc.c プロジェクト: jewlenchow/MQX_3.8.1
/*FUNCTION****************************************************************
*
* Function Name    : _real_time_to_sec
* Returned Value   : none
* Comments         :
*    This function convert date to secs since 1.1.1970 0:0:0".
*
*END*********************************************************************/
static uint_32 _date_to_sec( DATE_STRUCT_PTR time )
{
    #define SEC_IN_MIN  60
    #define SEC_IN_HOUR 3600
    #define SEC_IN_DAY  86400
    #define FEBRUARY    2
    #define ZERO_YEAR   1970

    static const uint_16 days_no_table[]= { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    uint_32 days = 0;
    uint_32 month;
    uint_32 year;

    days = 365 * (time->YEAR - ZERO_YEAR);
    /* get leap year */
    for( year = ZERO_YEAR; year < time->YEAR; year++)
    {
        days += _is_leap_year( year );
    }

    for( month = 1; month < time->MONTH; month++)
    {
        days+= days_no_table[month - 1];
        /* is leap year? */
        if( month == FEBRUARY )
        {
            days+= _is_leap_year( time->YEAR );
        }
    }

    days += time->DAY-1;
    return days*SEC_IN_DAY + time->HOUR*SEC_IN_HOUR + time->MINUTE*SEC_IN_MIN + time->SECOND;
}
コード例 #2
0
ファイル: time.c プロジェクト: fhector/helenOS-0.5-Hector
/**
 * For specified year, month and day of month, returns which day of that year
 * it is.
 *
 * For example, given date 2011-01-03, the corresponding expression is:
 *     _day_of_year(111, 0, 3) == 2
 *
 * @param year Year (year 1900 = 0, can be negative).
 * @param mon Month (January = 0).
 * @param mday Day of month (First day is 1).
 * @return Day of year (First day is 0).
 */
static int _day_of_year(time_t year, time_t mon, time_t mday)
{
	static int mdays[] =
	    { 0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334 };
	static int leap_mdays[] =
	    { 0, 31, 60, 91, 121, 152, 182, 213, 244, 274, 305, 335 };

	return (_is_leap_year(year) ? leap_mdays[mon] : mdays[mon]) + mday - 1;
}
コード例 #3
0
ファイル: time.c プロジェクト: fhector/helenOS-0.5-Hector
/**
 * Week number of the year, assuming weeks start on monday.
 * If the week containing January 1st has four or more days in the new year,
 * then it is considered week 1. Otherwise, it is the last week of the previous
 * year, and the next week is week 1. Both January 4th and the first Thursday
 * of January are always in week 1.
 *
 * @param tm Normalized broken-down time.
 * @return The week number (1 - 53).
 */
static int _iso_week_number(const struct posix_tm *tm)
{
	int day = tm->tm_yday - _wbyear_offset(tm->tm_year);
	if (day < 0) {
		/* Last week of previous year. */
		return 53;
	}
	if (day > 364 + _is_leap_year(tm->tm_year)) {
		/* First week of next year. */
		return 1;
	}
	/* All the other days give correct answer. */
	return (day / 7 + 1);
}
コード例 #4
0
ファイル: time.c プロジェクト: fhector/helenOS-0.5-Hector
/**
 * Returns week-based year of the specified time.
 *
 * @param tm Normalized broken-down time.
 * @return Week-based year.
 */
static int _wbyear(const struct posix_tm *tm)
{
	int day = tm->tm_yday - _wbyear_offset(tm->tm_year);
	if (day < 0) {
		/* Last week of previous year. */
		return tm->tm_year - 1;
	}
	if (day > 364 + _is_leap_year(tm->tm_year)) {
		/* First week of next year. */
		return tm->tm_year + 1;
	}
	/* All the other days are in the calendar year. */
	return tm->tm_year;
}
コード例 #5
0
ファイル: time.c プロジェクト: fhector/helenOS-0.5-Hector
/**
 * Returns how many days there are in the given month of the given year.
 * Note that year is only taken into account if month is February.
 *
 * @param year Year since 1900 (can be negative).
 * @param mon Month of the year. 0 for January, 11 for December.
 * @return Number of days in the specified month.
 */
static int _days_in_month(time_t year, time_t mon)
{
	assert(mon >= 0 && mon <= 11);

	static int month_days[] =
		{ 31, 0, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };

	if (mon == 1) {
		year += 1900;
		/* february */
		return _is_leap_year(year) ? 29 : 28;
	} else {
		return month_days[mon];
	}
}
コード例 #6
0
ファイル: rtpdate.c プロジェクト: layerfsd/cifssmb
/** @memo   Retrieve the current system date.

    @doc    Retrieves the current system date and returns it in the
    storage location.

    @precondition The baseReference must refer to a valid date.

    @return 0 on success. -1 otherwise.
 */
int rtp_get_date (
  RTP_DATE *date                /** Storage location for the current system date. */
  )
{
unsigned long deltaSecs;

	*date = baseReference.referenceDate;

    deltaSecs = rtp_get_system_sec() - baseReference.syncTime;
    
    if (deltaSecs > 0)
    {
		date->second += deltaSecs;  
		date->second %= 60;    
		deltaSecs /= 60;

	    if (deltaSecs > 0)
	    {
			date->minute += deltaSecs;  
			date->minute %= 60;    
			deltaSecs /= 60;

		    if (deltaSecs > 0)
		    {
				date->hour += deltaSecs;  
				date->hour %= 24;    
				deltaSecs /= 24;

			    if (deltaSecs > 0)
			    {
			    	int total_days;
			    	
					date->day += deltaSecs;  
					date->day %= 24;    
					deltaSecs /= 24;
					
					if (_is_leap_year(date->year))
					{
						total_days = month_start_leap[date->month] + date->day + deltaSecs;
					}
					else
					{
						total_days = month_start[date->month] + date->day + deltaSecs;
					}
					
					while (1)
					{
						if (_is_leap_year(date->year))
						{
							if (total_days < 366)
							{
								break;
							}							
							total_days -= 366;
						}
						else
						{
							if (total_days < 365)
							{
								break;
							}
							total_days -= 365;
						}
						
						date->year++;
					}

					if (_is_leap_year(date->year))
					{
						for (date->month=0; 
						     date->month < 11 && month_start_leap[date->month + 1] < total_days; 
						     date->month++) 
						{;}
						
						date->day = total_days - month_start_leap[date->month] + 1;
					}
					else
					{
						for (date->month=0; 
						     date->month < 11 && month_start[date->month + 1] < total_days; 
						     date->month++) 
						{;}
						
						date->day = total_days - month_start[date->month] + 1;
					}
					
					date->month++;					
			    }
		    }
	    }
	}

	return (0);
}
コード例 #7
0
ファイル: time.c プロジェクト: fhector/helenOS-0.5-Hector
/**
 * Normalizes the broken-down time and optionally adds specified amount of
 * seconds.
 * 
 * @param tm Broken-down time to normalize.
 * @param sec_add Seconds to add.
 * @return 0 on success, -1 on overflow
 */
static int _normalize_time(struct posix_tm *tm, time_t sec_add)
{
	// TODO: DST correction

	/* Set initial values. */
	time_t sec = tm->tm_sec + sec_add;
	time_t min = tm->tm_min;
	time_t hour = tm->tm_hour;
	time_t day = tm->tm_mday - 1;
	time_t mon = tm->tm_mon;
	time_t year = tm->tm_year;

	/* Adjust time. */
	min += _floor_div(sec, SECS_PER_MIN);
	sec = _floor_mod(sec, SECS_PER_MIN);
	hour += _floor_div(min, MINS_PER_HOUR);
	min = _floor_mod(min, MINS_PER_HOUR);
	day += _floor_div(hour, HOURS_PER_DAY);
	hour = _floor_mod(hour, HOURS_PER_DAY);

	/* Adjust month. */
	year += _floor_div(mon, 12);
	mon = _floor_mod(mon, 12);

	/* Now the difficult part - days of month. */
	
	/* First, deal with whole cycles of 400 years = 146097 days. */
	year += _floor_div(day, 146097) * 400;
	day = _floor_mod(day, 146097);
	
	/* Then, go in one year steps. */
	if (mon <= 1) {
		/* January and February. */
		while (day > 365) {
			day -= _is_leap_year(year) ? 366 : 365;
			year++;
		}
	} else {
		/* Rest of the year. */
		while (day > 365) {
			day -= _is_leap_year(year + 1) ? 366 : 365;
			year++;
		}
	}
	
	/* Finally, finish it off month per month. */
	while (day >= _days_in_month(year, mon)) {
		day -= _days_in_month(year, mon);
		mon++;
		if (mon >= 12) {
			mon -= 12;
			year++;
		}
	}
	
	/* Calculate the remaining two fields. */
	tm->tm_yday = _day_of_year(year, mon, day + 1);
	tm->tm_wday = _day_of_week(year, mon, day + 1);
	
	/* And put the values back to the struct. */
	tm->tm_sec = (int) sec;
	tm->tm_min = (int) min;
	tm->tm_hour = (int) hour;
	tm->tm_mday = (int) day + 1;
	tm->tm_mon = (int) mon;
	
	/* Casts to work around libc brain-damage. */
	if (year > ((int)INT_MAX) || year < ((int)INT_MIN)) {
		tm->tm_year = (year < 0) ? ((int)INT_MIN) : ((int)INT_MAX);
		return -1;
	}
	
	tm->tm_year = (int) year;
	return 0;
}