int
week(int day, int month, int year)
{
int yearday;
int firstweekday;
int weekday;
int firstday;
int firstsunday;
int shift;
if (mflag)
return isoweek(day, month, year);
yearday = day_in_year(day, month, year);
firstweekday = day_in_week(1, 1, year) + 1;
weekday = day_in_week(day, month, year) + 1;
firstday = day_in_year(1, 1, year);
firstsunday = firstday + (8 - firstweekday);
shift = 1;
if (yearday < firstsunday)
return (1);
if (firstweekday > THURSDAY - 1)
shift = 2;
return ((((yearday + 1) - (weekday - 1)) / 7) + shift);
}
/*
* day_array --
* Fill in an array of 42 integers with a calendar. Assume for a moment
* that you took the (maximum) 6 rows in a calendar and stretched them
* out end to end. You would have 42 numbers or spaces. This routine
* builds that array for any month from Jan. 1 through Dec. 9999.
*/
void
day_array(int day, int month, int year, int *days) {
int julday, daynum, dw, dm;
int *d_sep1752;
if (month == 9 && year == 1752) {
int sep1752_ofs = (weekstart + SEP1752_OFS) % 7;
d_sep1752 = julian ? j_sep1752 : sep1752;
memcpy(days, d_sep1752 + sep1752_ofs, MAXDAYS * sizeof(int));
for (dm=0; dm<MAXDAYS; dm++)
if (j_sep1752[dm + sep1752_ofs] == day)
days[dm] |= TODAY_FLAG;
return;
}
memcpy(days, empty, MAXDAYS * sizeof(int));
dm = days_in_month[leap_year(year)][month];
dw = (day_in_week(1, month, year) - weekstart + 7) % 7;
julday = day_in_year(1, month, year);
daynum = julian ? julday : 1;
while (dm--) {
days[dw] = daynum++;
if (julday++ == day)
days[dw] |= TODAY_FLAG;
dw++;
}
}
/*
* day_in_week
* return the 0 based day number for any date from 1 Jan. 1 to
* 31 Dec. 9999. Assumes the Gregorian reformation eliminates
* 3 Sep. 1752 through 13 Sep. 1752. Returns Thursday for all
* missing days.
*/
int
day_in_week(int day, int month, int year) {
long temp;
temp = (long)(year - 1) * 365 + leap_years_since_year_1(year - 1)
+ day_in_year(day, month, year);
if (temp < FIRST_MISSING_DAY)
return ((temp - 1 + SATURDAY) % 7);
if (temp >= (FIRST_MISSING_DAY + NUMBER_MISSING_DAYS))
return (((temp - 1 + SATURDAY) - NUMBER_MISSING_DAYS) % 7);
return (THURSDAY);
}
/*
* day_array --
* Fill in an array of 42 integers with a calendar. Assume for a moment
* that you took the (maximum) 6 rows in a calendar and stretched them
* out end to end. You would have 42 numbers or spaces. This routine
* builds that array for any month from Jan. 1 through Dec. 9999.
*/
void
day_array(int month, int year, int *days)
{
int day, dw, dm;
if (month == 9 && year == 1752) {
memmove(days, sep1752, MAXDAYS * sizeof(int));
return;
}
memmove(days, empty, MAXDAYS * sizeof(int));
dm = days_in_month[leap_year(year)][month];
dw = day_in_week(mflag?0:1, month, year);
day = julian ? day_in_year(1, month, year) : 1;
while (dm--)
days[dw++] = day++;
}
// number of days since Jan 1, 1970 (day 0)
long int days_linear(const Date& d)
{
if (d.year() < first_date.year()) error("days_linear: year must be 1970 or later");
int y = d.year() - first_date.year();
return y*365 + n_leapyears(d.year()) + day_in_year(d) - 1;
}
int
main(int argc, char **argv) {
struct tm *local_time;
time_t now;
int ch, day, month, year, yflag;
char *progname, *p;
int num_months = NUM_MONTHS;
progname = argv[0];
if ((p = strrchr(progname, '/')) != NULL)
progname = p+1;
__progname = progname;
setlocale(LC_ALL, "");
bindtextdomain(PACKAGE, LOCALEDIR);
textdomain(PACKAGE);
#if defined(HAVE_LIBNCURSES) || defined(HAVE_LIBNCURSESW) || defined(HAVE_LIBTERMCAP)
if ((term = getenv("TERM"))) {
int ret;
my_setupterm(term, 1, &ret);
if (ret > 0) {
Senter = my_tgetstr("so","smso");
Sexit = my_tgetstr("se","rmso");
Slen = strlen(Senter) + strlen(Sexit);
}
}
#endif
/*
* The traditional Unix cal utility starts the week at Sunday,
* while ISO 8601 starts at Monday. We read the start day from
* the locale database, which can be overridden with the
* -s (Sunday) or -m (Monday) options.
*/
#if HAVE_DECL__NL_TIME_WEEK_1STDAY
/*
* You need to use 2 locale variables to get the first day of the week.
* This is needed to support first_weekday=2 and first_workday=1 for
* the rare case where working days span across 2 weeks.
* This shell script shows the combinations and calculations involved:
for LANG in en_US ru_RU fr_FR csb_PL POSIX; do
printf "%s:\t%s + %s -1 = " $LANG $(locale week-1stday first_weekday)
date -d"$(locale week-1stday) +$(($(locale first_weekday)-1))day" +%w
done
en_US: 19971130 + 1 -1 = 0 #0 = sunday
ru_RU: 19971130 + 2 -1 = 1
fr_FR: 19971201 + 1 -1 = 1
csb_PL: 19971201 + 2 -1 = 2
POSIX: 19971201 + 7 -1 = 0
*/
{
int wfd;
union { unsigned int word; char *string; } val;
val.string = nl_langinfo(_NL_TIME_WEEK_1STDAY);
wfd = val.word;
wfd = day_in_week(wfd % 100, (wfd / 100) % 100, wfd / (100 * 100));
weekstart = (wfd + *nl_langinfo(_NL_TIME_FIRST_WEEKDAY) - 1) % 7;
}
#endif
yflag = 0;
while ((ch = getopt(argc, argv, "13mjsyV")) != -1)
switch(ch) {
case '1':
num_months = 1; /* default */
break;
case '3':
num_months = 3;
break;
case 's':
weekstart = 0; /* default */
break;
case 'm':
weekstart = 1;
break;
case 'j':
julian = 1;
break;
case 'y':
yflag = 1;
break;
case 'V':
printf(_("%s from %s\n"),
progname, PACKAGE_STRING);
return 0;
case '?':
default:
usage();
}
argc -= optind;
argv += optind;
time(&now);
local_time = localtime(&now);
day = month = year = 0;
switch(argc) {
case 3:
if ((day = atoi(*argv++)) < 1 || day > 31)
errx(1, _("illegal day value: use 1-%d"), 31);
/* FALLTHROUGH */
case 2:
if ((month = atoi(*argv++)) < 1 || month > 12)
errx(1, _("illegal month value: use 1-12"));
/* FALLTHROUGH */
case 1:
if ((year = atoi(*argv)) < 1 || year > 9999)
errx(1, _("illegal year value: use 1-9999"));
if (day) {
int dm = days_in_month[leap_year(year)][month];
if (day > dm)
errx(1, _("illegal day value: use 1-%d"), dm);
day = day_in_year(day, month, year);
} else if ((local_time->tm_year + 1900) == year) {
day = local_time->tm_yday + 1;
}
if (!month)
yflag=1;
break;
case 0:
day = local_time->tm_yday + 1;
year = local_time->tm_year + 1900;
month = local_time->tm_mon + 1;
break;
default:
usage();
}
headers_init();
if (!isatty(1))
day = 0; /* don't highlight */
if (yflag && julian)
j_yearly(day, year);
else if (yflag)
yearly(day, year);
else if (num_months == 1)
monthly(day, month, year);
else if (num_months == 3)
monthly3(day, month, year);
exit(0);
}
