コード例 #1
0
static RenderObject* nextSiblingRenderer(const Text& textNode)
{
    if (textNode.renderer())
        return textNode.renderer()->nextSibling();
    for (Node* sibling = NodeRenderingTraversal::nextSibling(&textNode); sibling; sibling = NodeRenderingTraversal::nextSibling(sibling)) {
        RenderObject* renderer = sibling->renderer();
        if (renderer && !isRendererReparented(renderer))
            return renderer;
    }
    return 0;
}
コード例 #2
0
static RenderObject* nextSiblingRenderer(const Element& element, const ContainerNode* renderingParentNode)
{
    // Avoid an O(N^2) problem with this function by not checking for
    // nextRenderer() when the parent element hasn't attached yet.
    // FIXME: Why would we get here anyway if parent is not attached?
    if (renderingParentNode && !renderingParentNode->attached())
        return 0;
    for (Node* sibling = NodeRenderingTraversal::nextSibling(&element); sibling; sibling = NodeRenderingTraversal::nextSibling(sibling)) {
        RenderObject* renderer = sibling->renderer();
        if (renderer && !isRendererReparented(renderer))
            return renderer;
    }
    return 0;
}
コード例 #3
0
RenderObject* NodeRenderingContext::nextRenderer() const
{
    if (RenderObject* renderer = m_node->renderer())
        return renderer->nextSibling();

    Element* element = m_node->isElementNode() ? toElement(m_node) : 0;
    if (element && element->shouldBeReparentedUnderRenderView(m_style.get())) {
        // FIXME: Reparented renderers not in the top layer should probably be
        // ordered in DOM tree order. We don't have a good way to do that yet,
        // since NodeRenderingTraversal isn't aware of reparenting. It's safe to
        // just append for now; it doesn't disrupt the top layer rendering as
        // the layer collection in RenderLayer only requires that top layer
        // renderers are orderered correctly relative to each other.
        if (!element->isInTopLayer())
            return 0;

        const Vector<RefPtr<Element> >& topLayerElements = element->document()->topLayerElements();
        size_t position = topLayerElements.find(element);
        ASSERT(position != notFound);
        for (size_t i = position + 1; i < topLayerElements.size(); ++i) {
            if (RenderObject* renderer = topLayerElements[i]->renderer())
                return renderer;
        }
        return 0;
    }

    if (m_parentFlowRenderer)
        return m_parentFlowRenderer->nextRendererForNode(m_node);

    // Avoid an O(N^2) problem with this function by not checking for
    // nextRenderer() when the parent element hasn't attached yet.
    if (m_renderingParent && !m_renderingParent->attached())
        return 0;

    for (Node* sibling = NodeRenderingTraversal::nextSibling(m_node); sibling; sibling = NodeRenderingTraversal::nextSibling(sibling)) {
        RenderObject* renderer = sibling->renderer();
        if (renderer && !isRendererReparented(renderer))
            return renderer;
    }

    return 0;
}
コード例 #4
0
RenderObject* NodeRenderingContext::previousRenderer() const
{
    if (RenderObject* renderer = m_node->renderer())
        return renderer->previousSibling();

    // FIXME: This doesn't work correctly for reparented elements that are
    // display: none. We'd need to duplicate the logic in nextRenderer, but since
    // nothing needs that yet just assert.
    ASSERT(!m_node->isElementNode() || !toElement(m_node)->shouldBeReparentedUnderRenderView(m_style.get()));

    if (m_parentFlowRenderer)
        return m_parentFlowRenderer->previousRendererForNode(m_node);

    // FIXME: We should have the same O(N^2) avoidance as nextRenderer does
    // however, when I tried adding it, several tests failed.
    for (Node* sibling = NodeRenderingTraversal::previousSibling(m_node); sibling; sibling = NodeRenderingTraversal::previousSibling(sibling)) {
        RenderObject* renderer = sibling->renderer();
        if (renderer && !isRendererReparented(renderer))
            return renderer;
    }

    return 0;
}