コード例 #1
0
ファイル: keys.c プロジェクト: JinfengChen/pblat
static struct exp *parseOrExp()
/* Parse lowest level of precedent expressions - or and xor. */
{
    struct exp *left;
    struct exp *right, *exp;
    struct kxTok *tok;
    enum kxTokType type;

    if ((left = parseAndExp()) == NULL)
        return NULL;
    if ((tok = token) == NULL)
        return left;
    type = token->type;
    if (type == kxtOr || type == kxtXor)
    {
        advanceToken();
        right = nextExp();
        if (right == NULL)
            errAbort("Expecting expression on the other side of %s", tok->string);
        AllocVar(exp);
        exp->left = left;
        exp->right = right;
        if (type == kxtOr)
            exp->type = kxOr;
        else
            exp->type = kxXor;
        return exp;
    }
    else
        return left;
}
コード例 #2
0
ファイル: keys.c プロジェクト: JinfengChen/pblat
static struct exp *parseAndExp()
/* Parse and level expressions. */
{
    struct exp *left;
    struct exp *right, *exp;
    struct kxTok *tok;
    enum kxTokType type;

    if ((left = parseNot()) == NULL)
        return NULL;
    if ((tok = token) == NULL)
        return left;
    type = token->type;
    if (type == kxtAnd)
    {
        advanceToken();
        right = nextExp();
        if (right == NULL)
            errAbort("Expecting expression on the other side of %s", tok->string);
        AllocVar(exp);
        exp->left = left;
        exp->right = right;
        exp->type = kxAnd;
        return exp;
    }
    else
        return left;
}
コード例 #3
0
ファイル: keys.c プロジェクト: JinfengChen/pblat
static struct exp *parseExp(struct kxTok *tokList)
/* Convert key expression from token stream to parse tree. */
{
    struct exp *exp;
    token = tokList;
    exp =  nextExp();
    if (token->type != kxtEnd)
    {
        errAbort("Extra tokens past end of expression.  Missing &?");
    }
    return exp;
}
コード例 #4
0
ファイル: keys.c プロジェクト: JinfengChen/pblat
static struct exp *parseNot()
/* Parse not */
{
    struct exp *exp;
    struct exp *right;

    if (token == NULL)
        return NULL;
    if (token->type == kxtNot)
    {
        advanceToken();
        right = nextExp();
        AllocVar(exp);
        exp->right = right;
        exp->type = kxNot;
        return exp;
    }
    else
        return parseParenthesized();
}
コード例 #5
0
ファイル: keys.c プロジェクト: JinfengChen/pblat
static struct exp *parseParenthesized()
/* Parse parenthesized expressions. */
{
    struct exp *exp;
    if (token == NULL)
        return NULL;
    if (token->type == kxtOpenParen)
    {
        advanceToken();
        exp = nextExp();
        if (token->type != kxtCloseParen)
            errAbort("Unmatched parenthesis");
        advanceToken();
        return exp;
    }
    else
    {
        return parseRelation();
    }
}
コード例 #6
0
long ZeckendorfLogarithm(mpz_class n,  mpz_class a) {
  /* Check that the input is valid. */
  /* Construct our "Fibonacci iterator" to keep track of where we are in the
   * Fibonacci sequence, including both the base and the logarithm.
   */
  //std::pair<T, T>             fibExponentIterator(T(1), a);
  //std::pair<Integer, Integer> fibBaseIterator(0u, 1u);
  mpz_class first(1);
  mpz_class second(a);
  mpz_class b_first(0);
  mpz_class b_second(1);
  
  /* Keep marching the iterator forward until we arrive at n. */
  while (second<n ) {
    /* Compute the next value in the generalized Fibonacci sequence as
     *
     *   (F(k), F(k+1)) -> (F(k+1), F(k+2))
     */
    
    mpz_class nextExp(first * second);
    cout<<nextExp<<endl;
    first = second;
    second = nextExp;

    mpz_class nextBase (b_first + b_second);
    cout<<nextBase<<endl;
    b_first = b_second;
    b_second = nextBase;
    
  }

  mpz_class result(0);

  /* Keep dividing out terms from the Zeckendorf representation of the number
   * until it reaches one.
   */
  while (b_first != 0) {
    /* If the first of the Fibonacci numbers is less than the current number,
     * divide it out and add the corresponding Fibonacci number to the
     * total.
     */
    if (b_first <= n) {
      n /= b_first;
      result += b_first;
    }

    /* Walk both iterators backward a step:
     *
     *   (F(k), F(k+1)) -> (F(k-1), F(k))
     */
    mpz_class prevExp (second / first);
    second = first;
    first  = prevExp;

    mpz_class prevBase (b_second - b_first);
    b_second = b_first;
    b_first = prevBase;
  }

  return result.get_si();
}