BoVector<T> operator* (const BoVector<T>& bv1, const BoVector<T>& bv2) {
// 相乘的两个BoVector需要大小相同
BoVector<T> rv;
for (int i=0; i<bv1.getsize(); i++) {
rv.push(bv1.get(i)*bv2.get(i)); // 类型必须支持*操作
}
return rv;
}
BoVector<BoVectorType> operator*(BoVector<BoVectorType>&rhs1, BoVector<BoVectorType>&rhs2)
{
BoVector<BoVectorType> return_element;
for(int i = 0; i < rhs1.getSize(); i++)
{
return_element.push(rhs1.get(i) * rhs2.get(i));
}
return return_element;
}
int main(int argc, const char * argv[])
{
cout << square<int>(5) << endl;
cout << square<double>(5.5) << endl;
BoVector<int> bv;
bv.push(1);
bv.push(2);
bv.push(3);
bv.push(4);
bv.print_Vector();
//square bv tries to square the vector by passing it as an argument
//we overloaded the * operator for bv vector multiplication
bv = square(bv);
bv.print_Vector();
return 0;
}
int main(void) {
// STL template 利用范型减少了因类型不同而重复的代码
// 但是实际内存中存储的任然是 code bloat
cout << square<int>(5) << endl;
cout << square<double>(5.5) << endl;
BoVector<int> bv;
bv.push(1); bv.push(3); bv.push(1); bv.push(4);
bv.print();
bv = square< BoVector<int> >(bv);
bv.print();
return 0;
}
