예제 #1
0
/* Given two trees, should return true if they are
   mirror of each other. */
int areMirror(Node* a, Node* b)
{
    if(!a && !b)
        return 1;
    if(!a || !b)
        return 0;
    if(a->data == b->data && areMirror(a->left, b->right) && areMirror(a->right, b->left))
        return 1;
    return 0;
}
int areMirror(struct Node* a, struct Node* b)
{
    if (a == NULL && b == NULL)
        return 1;
    if (a == NULL || b == NULL)
        return NULL;

    return (a->data == b->data) &&
            areMirror(a->left, b->right) &&
	    areMirror(a->right, b->left);
}
int main()
{
    Node *a = newNode(1);
    Node *b = newNode(1);
    a->left = newNode(2);
    a->right = newNode(3);
    a->left->left  = newNode(4);
    a->left->right = newNode(5);

    b->left = newNode(3);
    b->right = newNode(2);
    b->right->left = newNode(5);
    b->right->right = newNode(4);

    areMirror(a, b)? printf("Yes") : printf("No");
    
    return 0;
}