예제 #1
0
void mem_pestat(const mem_opt_t *opt, int64_t l_pac, int n, const mem_alnreg_v *regs, mem_pestat_t pes[4]) {
  int i, d, max;
  uint64_v isize[4];
  memset(pes, 0, 4 * sizeof(mem_pestat_t));
  memset(isize, 0, sizeof(kvec_t(int)) * 4);
  /* infer based on the first reg from the two reads */
  for (i = 0; i < n>>1; ++i) {
    int dir;
    int64_t is;
    mem_alnreg_v *r[2];
    r[0] = (mem_alnreg_v*)&regs[i<<1|0];
    r[1] = (mem_alnreg_v*)&regs[i<<1|1];
    if (r[0]->n == 0 || r[1]->n == 0) continue;
    if (cal_sub(opt, r[0]) > MIN_RATIO * r[0]->a[0].score) continue;
    if (cal_sub(opt, r[1]) > MIN_RATIO * r[1]->a[0].score) continue;
    if (r[0]->a[0].rid != r[1]->a[0].rid) continue; // not on the same chr
    if (r[0]->a[0].bss != r[1]->a[0].bss) continue; /* not on the same bisulfite strand */
    dir = mem_infer_dir(l_pac, r[0]->a[0].rb, r[1]->a[0].rb, &is);
    if (is && is <= opt->max_ins) kv_push(uint64_t, isize[dir], is);
  }
  if (bwa_verbose >= 3) fprintf(stderr, "[M::%s] # candidate unique pairs for (FF, FR, RF, RR): (%ld, %ld, %ld, %ld)\n", __func__, isize[0].n, isize[1].n, isize[2].n, isize[3].n);
  for (d = 0; d < 4; ++d) { // TODO: this block is nearly identical to the one in bwtsw2_pair.c. It would be better to merge these two.
    mem_pestat_t *r = &pes[d];
    uint64_v *q = &isize[d];
    int p25, p50, p75, x;
    if (q->n < MIN_DIR_CNT) {
      fprintf(stderr, "[M::%s] skip orientation %c%c as there are not enough pairs\n", __func__, "FR"[d>>1&1], "FR"[d&1]);
      r->failed = 1;
      free(q->a);
      continue;
    } else fprintf(stderr, "[M::%s] analyzing insert size distribution for orientation %c%c...\n", __func__, "FR"[d>>1&1], "FR"[d&1]);
예제 #2
0
파일: brain.c 프로젝트: Namibnat/braincalc
int main(int argc, char **argv)
{
  double time_spent;               /* To add time */
  int time_spent_m, time_spent_s;  /* To add time */
  time_t begin, end;               /* To add time */
  int i, r, n1, n2;
  int rounds, maxnum; /* rounds is how many iterations of the game there will be
                         maxnum is the biggest values used in the sums */
  int score = 0;
  /* initial settings for rounds & turns */
  rounds = (argv[1] && isdigit(argv[1][0])) ? atoi(argv[1]) : ROUNDS;
  maxnum = (argv[2] && isdigit(argv[2][0])) ? atoi(argv[2]) : MAXNUM;
  /* start the timer */
  begin = time(NULL);
  /* return HOWTO instead of play */
  if(argv[1] && (argv[1][0] == 'h')){
    help();
    return 0;
  }
  /* the main dispach switch */
  srand ( (unsigned)time ( NULL ) );
  for(i = 0; i < rounds; i++){
    r = rand() % 4;
    n1 = rand() % maxnum;
    n2 = rand() % maxnum;
    switch(r){
    case 0: /* addition */
      score += cal_add(n1, n2);
      break;
    case 1: /* subtraction - call function with biggest number first,
                             so we don't need to have negatives in the answer */
      score += (n1 >= n2) ? cal_sub(n1, n2) : cal_sub(n2, n1);
      break;
    case 2: /* multiplication */
      score += cal_mul(n1, n2);
      break;
    case 3: /* division - we avoid 0 in the division, just to simplify things
                          like subtraction, we also use the bigger val divided by the smaller */
      while(n1 == 0 || n2 == 0){
	n1 = rand() % MAXNUM;
	n2 = rand() % MAXNUM;
      }
      score += (n1 >= n2) ? cal_div(n1, n2) : cal_sub(n2, n1);
      break;
    default: /* catch imposible */
      printf("Something isn't working rights\n");
      return 0;
    }
  }
  /* end timer */
  end = time(NULL);
  time_spent = difftime(end, begin);
  time_spent_m = (int)(time_spent)/60;
  time_spent_s = (int)(time_spent)%60;

  /* Report */
  printf("\n");
  printf("You got %d out of %d in %d ", score, rounds, time_spent_m);
  printf("%s", (time_spent_m == 1)?"minute":"minutes");
  printf(", %d ", time_spent_s);
  printf("%s", (time_spent_s == 1)?"second":"seconds");
  if((rounds - score) < 4){
    printf("!");
  }
  else{
    printf(".");
  }
  printf("\n\n");
  return 0;
}