예제 #1
0
 void findright(TreeLinkNode* root, int depth, TreeLinkNode* &rst) {
     if(!root) {
         return;
     }
     
     if(!depth) {
         rst = root;
         return;
     }
     
     
     findright(root->left,depth-1,rst);
     findright(root->right,depth-1,rst);
     
     
 }
예제 #2
0
파일: test.cpp 프로젝트: tcliuyong/C-CPP
int main()
{
Point p[100];
 int n;//输入测试数据的组数
 cin>>n;

  for(int i=0;i<n;i++)//下面开始输入测试数据
  {
   cin>>p[i].x>>p[i].y;
  }
  sort(p,p+n,compare);
  result.push_back(0);//这是两上端点,不用比较,直接保存
  result.push_back(n-1);
  findleft(p,0,n-1);//调用函数
  findright(p,0,n-1);
  cout<<"组成凸包的点为:"<<endl;
  int len=result.size();
  cout<<len<<endl;
  for(int i=0;i<len;i++)
  {
  	pnt[i].x=p[result[i]].x;
  	pnt[i].y=p[result[i]].y;
  	cout<<i<<"("<<pnt[i].x<<","<<pnt[i].y<<")"<<" ";
  }
  cout<<"fsd"<<endl;
  	ace(pnt,len);
  
  result.clear();
}
예제 #3
0
    void connectSub(TreeLinkNode* left,TreeLinkNode* right) {
        TreeLinkNode* p=NULL, *q=NULL;
        
        int len = min(level(left),level(right));
        for(int i = 0; i < len; ++i) {
            findright(left,i,p);
            findleft(right,i,q);

            p->next = q;
            
        }

    }