예제 #1
0
파일: inet_ntop.c 프로젝트: brho/netperf
const char *inet_ntop(int af, const void *src, char *dst, size_t size)
{
	switch (af) {
		case AF_INET:
			return inet_ntop_v4(src, dst, size);
		default:
			Set_errno(EAFNOSUPPORT);
			return NULL;
	}
}
예제 #2
0
const char *
inet_ntop(int af, const void *src, char *dst, socklen_t size)
{
    switch (af) {
    case AF_INET :
	return inet_ntop_v4 (src, dst, (size_t)size);
    default :
	errno = EAFNOSUPPORT;
	return NULL;
    }
}
예제 #3
0
JABBERD2_API const char *
_j_inet_ntop(int af, const void *src, char *dst, size_t size)
{
    switch (af) {
    case AF_INET :
	return inet_ntop_v4 (src, dst, size);
    default :
	errno = WSAEAFNOSUPPORT;
	return NULL;
    }
}
예제 #4
0
/*
 * Convert IPv6 binary address into presentation (printable) format.
 */
static const char* inet_ntop_v6 (const u_char *src, char *dst, size_t size)
{
  /*
   * Note that int32_t and int16_t need only be "at least" large enough
   * to contain a value of the specified size.  On some systems, like
   * Crays, there is no such thing as an integer variable with 16 bits.
   * Keep this in mind if you think this function should have been coded
   * to use pointer overlays.  All the world's not a VAX.
   */
  char  tmp [INET6_ADDRSTRLEN+1];
  char *tp;
  struct {
    long base;
    long len;
  } best, cur;
  u_long words [IN6ADDRSZ / INT16SZ];
  int    i;

  /* Preprocess:
   *  Copy the input (bytewise) array into a wordwise array.
   *  Find the longest run of 0x00's in src[] for :: shorthanding.
   */
  memset (words, 0, sizeof(words));
  for (i = 0; i < IN6ADDRSZ; i++)
      words[i/2] |= (src[i] << ((1 - (i % 2)) << 3));

  best.base = -1;
  cur.base  = -1;
  for (i = 0; i < (IN6ADDRSZ / INT16SZ); i++)
  {
    if (words[i] == 0)
    {
      if (cur.base == -1)
           cur.base = i, cur.len = 1;
      else cur.len++;
    }
    else if (cur.base != -1)
    {
      if (best.base == -1 || cur.len > best.len)
         best = cur;
      cur.base = -1;
    }
  }
  if ((cur.base != -1) && (best.base == -1 || cur.len > best.len))
     best = cur;
  if (best.base != -1 && best.len < 2)
     best.base = -1;

  /* Format the result.
   */
  tp = tmp;
  for (i = 0; i < (IN6ADDRSZ / INT16SZ); i++)
  {
    /* Are we inside the best run of 0x00's?
     */
    if (best.base != -1 && i >= best.base && i < (best.base + best.len))
    {
      if (i == best.base)
         *tp++ = ':';
      continue;
    }

    /* Are we following an initial run of 0x00s or any real hex?
     */
    if (i != 0)
       *tp++ = ':';

    /* Is this address an encapsulated IPv4?
     */
    if (i == 6 && best.base == 0 &&
        (best.len == 6 || (best.len == 5 && words[5] == 0xffff)))
    {
      if (!inet_ntop_v4(src+12, tp, sizeof(tmp) - (tp - tmp)))
      {
        errno = ENOSPC;
        return (NULL);
      }
      tp += strlen(tp);
      break;
    }
    tp += sprintf (tp, "%lX", words[i]);
  }

  /* Was it a trailing run of 0x00's?
   */
  if (best.base != -1 && (best.base + best.len) == (IN6ADDRSZ / INT16SZ))
     *tp++ = ':';
  *tp++ = '\0';

  /* Check for overflow, copy, and we're done.
   */
  if ((size_t)(tp - tmp) > size)
  {
    errno = ENOSPC;
    return (NULL);
  }
  return strcpy (dst, tmp);
  return (NULL);
}