C++ (Cpp) exception_type::GetMsg 예제들

예제 #1

파일: FuncTerm.cpp 프로젝트: asiaszmek/moose-core

void showError(mu::Parser::exception_type &e)
{
    cout << "Error occurred in parser.\n" 
         << "Message:  " << e.GetMsg() << "\n"
         << "Formula:  " << e.GetExpr() << "\n"
         << "Token:    " << e.GetToken() << "\n"
         << "Position: " << e.GetPos() << "\n"
         << "Error code:     " << e.GetCode() << endl;
}

예제 #2

파일: muParserInterface.cpp 프로젝트: CorentinVasseur/pacs

 void printMuException(mu::Parser::exception_type &e)
 {
   using std::cout;
   cout << "Content of muParser exception" << "\n";
   cout << "Message:  " << e.GetMsg() << "\n";
   cout << "Formula:  " << e.GetExpr() << "\n";
   cout << "Token:    " << e.GetToken() << "\n";
   cout << "Position: " << e.GetPos() << "\n";
   cout << "Errc:     " << e.GetCode() << "\n";
 }