void main( ) { struct sparse s[5] ; int i ; clrscr( ) ; for ( i = 0 ; i <= 4 ; i++ ) initsparse ( &s[i] ) ; create_array ( &s[0] ) ; create_tuple ( &s[1], s[0] ) ; display_tuple ( s[1] ) ; create_array ( &s[2] ) ; create_tuple ( &s[3], s[2] ) ; display_tuple ( s[3] ) ; addmat ( &s[4], s[1], s[3] ) ; printf ( "\nResult of addition of two matrices: " ) ; display_result ( s[4] ) ; for ( i = 0 ; i <= 4 ; i++ ) delsparse ( &s[i] ) ; getch( ) ; }
int main( ) { struct sparse s[5] ; int i ; system ( "cls" ) ; for ( i = 0 ; i <= 4 ; i++ ) initsparse ( &s[i] ) ; create_array ( &s[0] ) ; create_tuple ( &s[1], s[0] ) ; display_tuple ( s[1] ) ; create_array ( &s[2] ) ; create_tuple ( &s[3], s[2] ) ; display_tuple ( s[3] ) ; addmat ( &s[4], s[1], s[3] ) ; printf ( "Result of addition of two matrices:" ) ; display_result ( s[4] ) ; for ( i = 0 ; i <= 4 ; i++ ) delsparse ( &s[i] ) ; return 0 ; }
int main() { printf("**********************************************************\n"); printf(" 稀疏矩阵运算器 \n"); printf("**********************************************************\n"); int a=-1; while(a) { printf("功能列表\n\n"); printf("1.两个矩阵相加\n"); printf("2.两个矩阵相减\n"); printf("3.两个矩阵相乘\n\n"); printf("输入0退出程序\n\n"); printf("请输入你想使用功能对应的数字:"); int a,b,c,d; scanf("%d",&a); if(a==1) { mat x,y,z; printf("请输入第一个矩阵的行数和列数(不超过20):"); scanf("%d %d",&x.mu,&x.nu); printf("请输入第二个矩阵的行数和列数(不超过20):"); scanf("%d %d",&y.mu,&y.nu); if(x.nu!=y.nu||x.mu!=y.mu)printf("两个矩阵不匹配,无法相加\n\n"); else addmat(x,y,z); }//a==1 else if(a==2) { mat x,y,z; printf("请输入第一个矩阵的行数和列数(不超过20):"); scanf("%d %d",&x.mu,&x.nu); printf("请输入第二个矩阵的行数和列数(不超过20):"); scanf("%d %d",&y.mu,&y.nu); if(x.nu!=y.nu||x.mu!=y.mu)printf("两个矩阵不匹配,无法相减\n\n"); else subtmat(x,y,z); }//a==2 else if(a==3) { mat x,y,z; printf("请输入第一个矩阵的行数和列数(不超过20):"); scanf("%d %d",&x.mu,&x.nu); printf("请输入第二个矩阵的行数和列数(不超过20):"); scanf("%d %d",&y.mu,&y.nu); if(x.nu!=y.mu)printf("两个矩阵不匹配,无法相乘\n\n"); else multmat(x,y,z); }//a==3 else if(a==0)break; }//while return 0; }
int main() { int dim = 3; int A[][N] = {1,2,3,4,5,6,7,8,9}; // Matrix A int B[][N] = {9,8,7,6,5,4,3,2,1}; // Matrix B int C[N][N]; addmat(dim, A, B, C); for (int i = 0; i < dim; i ++) { for (int j = 0; j < N; j++) { printf("%d ", C[i][j]); } printf("\n"); } return 0; }