Exemplo n.º 1
0
int getGCD(int a, int b)
{
	if(b==0) 
		return a;
	else
		return getGCD(b, a%b);
}
Exemplo n.º 2
0
int main(void){
	char s[SIZE]; // hold the string that user inputs.
	int c; 
	int x; // x value to be input
	int y; // y value to be input
	int i = 0; // for loop count

	 // prompt user input data
	puts("Please enter two integer, and we can get GCD");
	printf("-------------------------------------------\n");
    
    	// user getchar to read each character
	while(i < SIZE - 1 && (c = getchar()) != '\n'){
		s[i++] = c;
	}
	s[i] = '\0'; // end the string
	
	sscanf(s, "%d%d", &x,&y); // Convert string into number 
	int gcd = getGCD(x,y); // Invoke function to get gcd
	printf("--------------------------------------------\n");
	if (gcd == 0){
             printf("Your input is wrong, GCD is based on non-negative number and not zero.\n");   
    	} else {
   	     printf("We can get GCD is %d for %d and %d\n", gcd, x, y); 
    	}

	system("pause");
	return 0;
}
Exemplo n.º 3
0
//get the least common multiple
int getLCM(int *array, int size){
    int x;
    int y;
    int temp;
    int gcd = 1;
    int result = 1;
    int i;

    x = array[0];
    for (i = 0; i < size - 1; ++i)
    {
        y = array[i+1];
        if (x < y)
        {
            temp = x;
            x = y;
            y = temp;
        }

        gcd = getGCD(x, y);

        printf("the gcd is: %d\n", gcd);

        result = (x * y) / gcd;

        x = result;
    }

    return result;
}
Exemplo n.º 4
0
void Q3() {
    int gcd, num, denom;
    printf("Enter a fraction: ");
    scanf("%d/%d", &num, &denom);
    
    gcd = getGCD(num, denom);
    
    printf("In lowest terms: %d/%d\n", num / gcd, denom / gcd);
}
Exemplo n.º 5
0
int getGCD(int x, int y){

    if (x % y == 0)
    {
        return y;
    }else{
        return getGCD(y, x % y);
    }
}
Exemplo n.º 6
0
void Menu::executeGCD() {
	int nFirst = 0, nSecond = 0;

	cout << "\t최대공약수 구하기 함수를 선택하셨습니다." << endl;
	cout << "■ 두 개의 숫자를 입력해주세요." << endl;
	cout << "- 첫 번째 수 : ";
	cin >> nFirst;

	cout << "- 두 번째 수 : ";
	cin >> nSecond;

	int nGcd = getGCD(nFirst, nSecond);

	cout << "▶ " << nFirst << "와 " << nSecond << "의 최대공약수는 " << nGcd << " 입니다." << endl;
}
Exemplo n.º 7
0
int getLCM(int a, int b)
{
	return (a*b)/getGCD(a, b);
}