Exemplo n.º 1
0
int main() {
	bi_initialize();
	int k = 2;
	bigint f1 = int_to_bi(1), f2 = int_to_bi(1), f3, tmp;
	bigint zeros = int_to_bi(1000000000);
	while (1) {
		k++;
		f3 = bi_add(f1, bi_copy(f2));
		int mod = bi_int_mod(bi_copy(f3), 1000000000);
		if (mod >= 100000000) {
			if (is_pandigital(mod)) {
				tmp = bi_copy(f3);
				while (bi_compare(bi_copy(tmp), bi_copy(zeros)) > 0) {
					tmp = bi_int_divide(tmp, 10);
				}
				if (is_pandigital(bi_to_int(tmp))) {
					break;
				}
			}
		}
		f1 = f2;
		f2 = f3;
	}
	bi_free(f2);
	bi_free(f3);
	bi_free(zeros);
	printf("%d\n", k);
	bi_terminate();
	return 0;
}
Exemplo n.º 2
0
int main()
{
  double base = (1 + sqrt(5)) / 2.0;
  double norm = sqrt(5);
  int prev_lower = 1;
  int curr_lower = 1;
  int idx = 2;
  double high = (base * base) / norm;
  while(1)
    {
      int tmp = curr_lower;
      curr_lower = (prev_lower + curr_lower) % bound;
      prev_lower = tmp;
      high *= base;
      if (high >= bound)
        {
          high /= 10;
        }
      idx++;
      if (!is_pandigital(curr_lower))
        {
          continue;
        }
       if (!is_pandigital((int)high))
         {
           continue;
         }
      std::cout << idx << std::endl;
      break;
    }
  return 0;
}
Exemplo n.º 3
0
long solve() {
	long n = 5;
	long max = 7000001;
	while (n <= 7654321) {
		n += 2;
		if (is_pandigital(n) && common::is_prime_fast(n)) {
			max = n;
		}
		n += 4;
		if (is_pandigital(n) && common::is_prime_fast(n)) {
			max = n;
		}
	}
	return max;
}
Exemplo n.º 4
0
int main(){
  for(int i = 9487; i >= 9234; --i){
    int num = concat(i, 2*i);
    if(is_pandigital(num)){
      std::cout << num << std::endl;
      break;
    }
  }
}
int main(){
	std::set<int> products;
	for(int i = 2; i <= 100; i++){
		for(int j = 100; j <= 9999; j++){
			if(is_pandigital(i, j)) products.insert(i * j);
		}
	}
	std::cout << std::accumulate(products.begin(), products.end(), 0) << std::endl;
	return 0;
}
Exemplo n.º 6
0
Arquivo: 038.c Projeto: pqhieu/shovel
int main()
{
    long p = 0;
    for (long x = 9387; x >= 9234; --x) {
        p = concat(x, 2 * x);
        if (is_pandigital(p)) break;
    }

    printf("%ld\n", p);
    return 0;
}
long consec(long x) {
    int n = 1;
    long ans = 0;
    while(ans < 100000000) {
        ans = concat(ans, x * n);
        n++;
    }
    if(is_pandigital(ans))
        return ans;
    else
        return -1;
}
Exemplo n.º 8
0
int main() {
// NOTE: Unfortunately, I didn't figure the starting number out myself;
// I used 987654321 (which takes A LOT longer, about 4.5 minutes).
// Apparently, if the digital sum of a number is divisible by 3, the number isn't prime.
#define START 7654321
	for (uint32_t i = START; i > 0 && i <= START; i-=2) { /* detect underflow w/ i <= START */
		if (is_pandigital(i) && isprime(i)) {
			printf("Answer: %u\n", i);
			break;
		}
	}
	return 0;
}
Exemplo n.º 9
0
int main(int argc, char* argv) {
	__int8* prime_list = create_prime_list(MAX);

	for (unsigned long long i = MAX; i >= 0; i--) {
		if (is_prime(prime_list, i) && is_pandigital(i)) {
			printf("Pandigital + Prime: %llu\n", i);
			break;
		}
	}

	destroy_prime_list(prime_list);

	return 0;
}
Exemplo n.º 10
0
int main(void)
{
    initialize_primes();

    for(long long i = 987654321; i > 1; i--)
    {
	if(is_pandigital(i) && is_prime(i))
	{
	    printf("%lld\n", i);
	    return 0;
	}
    }
    
    return 1;
}
Exemplo n.º 11
0
int main(int argc, char* argv[]) {
  int n;
  long long int largest = 0;
  for (n=2; n<10; n++) {
    int i = 1;
    long long int p;
    while ((p = product(i, n)) < 1000000000LL) {
      if (is_pandigital(p)) {
        if (p > largest) largest = p;
      }
      i++;
    }
  }
  printf("%lli\n", largest);
  return 0;
}
Exemplo n.º 12
0
int main(int argc, char **argv)
{
    int aux, max = 0;
    char n[MAX_DIGITS + 1];
    for(int i = 9123; i < 9876; i++) {
        sprintf(n, "%d%d", i, 2*i);
        if(is_pandigital(n)) {
            aux = atoi(n);
            if(aux > max)
                max = aux;
        }
    }

    printf("%d\n", max);

    return 0;
}
Exemplo n.º 13
0
int main(void)
{
  printf("%i\n", is_pandigital(88) );
  printf("%i\n", is_pandigital(87) );
  printf("%i\n", is_pandigital(75423) );
  printf("%i\n", is_pandigital(453124) );
  
  printf("%i\n", is_pandigital(2143) );
  printf("%i\n", is_pandigital(625314) );

  exit(0);
}
Exemplo n.º 14
0
int main(void)
{

  int lim = 100000000; //9876543; //21;
  
  int *primes = malloc( lim * sizeof(int) );
  sleeve(primes, lim);

  int i = 1000;
  int best = 0;
  while( lim -i )
  {
    if ( primes[i] && is_pandigital(i) )
      best = i;
    i++;
  }
  
  printf("%i\n",best);
  
  free(primes);

  exit(0);
}
Exemplo n.º 15
0
int main(int argc, char ** argv)
{
	int a, b, product, sum;
	int * set, set_size, set_capacity;
	
	set_capacity = 2;
	set_size = 0;
	set = (int *) malloc(set_size * sizeof(int));
	
	for(a = 1; a < 100000; a++)
	{
		if(!is_pandigital(a))
			continue;
		for(b = a + 1; b < 100000 / a; b++)
		{
			product = a * b;
			if(a * b > 100000)
				break;
			if(is_pandigital3(a, b, product))
			{
				//printf("%d * %d == %d\n", a, b, product);
				set_append(set, &set_size, &set_capacity, product);
			}
		}
	}
	
	sum = 0;
	for(a = 0; a < set_size; a++)
		sum += set[a];
	
	printf("Sum of 1-9 pandigital products: %d\n", sum);

	free(set);

	return 0;
}
Exemplo n.º 16
0
int
main(int argc, char *argv[])
{
	int num, concat, i;
	int found = 0;

	for (num = NUM_START; num > 0; num--) {
		concat = 0;
		for (i = 1; ndigit(concat) < 9; i++) {
			concat = concatnum(concat, i * num);
			if (ndigit(concat) == 9 && is_pandigital(concat)) {
				found = 1;
				break;
			}
		}
		if (found)
			break;
	}
	if (!found)
		errx(1, "oops! not found...");
	printf("%d\n", concat);

	return 0;
}