static struct mtd_info *flash_probe(void)
{
struct mtd_info *mtd_cse0;
struct mtd_info *mtd_cse1;
struct mtd_info *mtd_cse;
mtd_cse0 = probe_cs(&map_cse0);
mtd_cse1 = probe_cs(&map_cse1);
if (!mtd_cse0 && !mtd_cse1) {
return NULL;
}
if (mtd_cse0 && mtd_cse1) {
struct mtd_info *mtds[] = { mtd_cse0, mtd_cse1 };
mtd_cse = mtd_concat_create(mtds, ARRAY_SIZE(mtds),
"cse0+cse1");
if (!mtd_cse) {
printk(KERN_ERR "%s and %s: Concatenation failed!\n",
map_cse0.name, map_cse1.name);
mtd_cse = mtd_cse0;
map_destroy(mtd_cse1);
}
} else {
mtd_cse = mtd_cse0? mtd_cse0 : mtd_cse1;
}
return mtd_cse;
}
static struct mtd_info *flash_probe(void)
{
struct mtd_info *mtd_cse0;
struct mtd_info *mtd_cse1;
struct mtd_info *mtd_total;
struct mtd_info *mtds[2];
int count = 0;
if ((mtd_cse0 = probe_cs(&map_cse0)) != NULL)
mtds[count++] = mtd_cse0;
if ((mtd_cse1 = probe_cs(&map_cse1)) != NULL)
mtds[count++] = mtd_cse1;
if (!mtd_cse0 && !mtd_cse1) {
return NULL;
}
if (count > 1) {
mtd_total = mtd_concat_create(mtds, count, "cse0+cse1");
if (!mtd_total) {
printk(KERN_ERR "%s and %s: Concatenation failed!\n",
map_cse0.name, map_cse1.name);
mtd_total = mtd_cse0;
map_destroy(mtd_cse1);
}
} else
mtd_total = mtd_cse0 ? mtd_cse0 : mtd_cse1;
return mtd_total;
}
static struct mtd_info *flash_probe(void)
{
struct mtd_info *mtd_cse0;
struct mtd_info *mtd_cse1;
struct mtd_info *mtd_nand = NULL;
struct mtd_info *mtd_total;
struct mtd_info *mtds[3];
int count = 0;
if ((mtd_cse0 = probe_cs(&map_cse0)) != NULL)
mtds[count++] = mtd_cse0;
if ((mtd_cse1 = probe_cs(&map_cse1)) != NULL)
mtds[count++] = mtd_cse1;
#ifdef CONFIG_ETRAX_NANDFLASH
if ((mtd_nand = crisv32_nand_flash_probe()) != NULL)
mtds[count++] = mtd_nand;
#endif
if (!mtd_cse0 && !mtd_cse1 && !mtd_nand) {
/* No chip found. */
return NULL;
}
if (count > 1) {
#ifdef CONFIG_MTD_CONCAT
/* Since the concatenation layer adds a small overhead we
* could try to figure out if the chips in cse0 and cse1 are
* identical and reprobe the whole cse0+cse1 window. But since
* flash chips are slow, the overhead is relatively small.
* So we use the MTD concatenation layer instead of further
* complicating the probing procedure.
*/
mtd_total = mtd_concat_create(mtds,
count,
"cse0+cse1+nand");
#else
printk(KERN_ERR "%s and %s: Cannot concatenate due to kernel "
"(mis)configuration!\n", map_cse0.name, map_cse1.name);
mtd_toal = NULL;
#endif
if (!mtd_total) {
printk(KERN_ERR "%s and %s: Concatenation failed!\n",
map_cse0.name, map_cse1.name);
/* The best we can do now is to only use what we found
* at cse0.
*/
mtd_total = mtd_cse0;
map_destroy(mtd_cse1);
}
} else {
mtd_total = mtd_cse0? mtd_cse0 : mtd_cse1 ? mtd_cse1 : mtd_nand;
}
return mtd_total;
}
/*
* Probe each chip select individually for flash chips. If there are chips on
* both cse0 and cse1, the mtd_info structs will be concatenated to one struct
* so that MTD partitions can cross chip boundries.
*
* The only known restriction to how you can mount your chips is that each
* chip select must hold similar flash chips. But you need external hardware
* to do that anyway and you can put totally different chips on cse0 and cse1
* so it isn't really much of a restriction.
*/
static struct mtd_info *flash_probe(void)
{
struct mtd_info *mtd_cse0;
struct mtd_info *mtd_cse1;
struct mtd_info *mtd_cse;
mtd_cse0 = probe_cs(&map_cse0);
mtd_cse1 = probe_cs(&map_cse1);
if (!mtd_cse0 && !mtd_cse1) {
/* No chip found. */
return NULL;
}
if (mtd_cse0 && mtd_cse1) {
#ifdef CONFIG_MTD_CONCAT
struct mtd_info *mtds[] = { mtd_cse0, mtd_cse1 };
/* Since the concatenation layer adds a small overhead we
* could try to figure out if the chips in cse0 and cse1 are
* identical and reprobe the whole cse0+cse1 window. But since
* flash chips are slow, the overhead is relatively small.
* So we use the MTD concatenation layer instead of further
* complicating the probing procedure.
*/
mtd_cse = mtd_concat_create(mtds,
sizeof(mtds) / sizeof(mtds[0]),
"cse0+cse1");
#else
printk(KERN_ERR "%s and %s: Cannot concatenate due to kernel "
"(mis)configuration!\n", map_cse0.name, map_cse1.name);
mtd_cse = NULL;
#endif
if (!mtd_cse) {
printk(KERN_ERR "%s and %s: Concatenation failed!\n",
map_cse0.name, map_cse1.name);
/* The best we can do now is to only use what we found
* at cse0.
*/
mtd_cse = mtd_cse0;
map_destroy(mtd_cse1);
}
} else {
mtd_cse = mtd_cse0? mtd_cse0 : mtd_cse1;
}
return mtd_cse;
}
static struct mtd_info *flash_probe(void)
{
struct mtd_info *mtd_cse0;
struct mtd_info *mtd_cse1;
struct mtd_info *mtd_total;
struct mtd_info *mtds[2];
int count = 0;
if ((mtd_cse0 = probe_cs(&map_cse0)) != NULL)
mtds[count++] = mtd_cse0;
if ((mtd_cse1 = probe_cs(&map_cse1)) != NULL)
mtds[count++] = mtd_cse1;
if (!mtd_cse0 && !mtd_cse1) {
/* No chip found. */
return NULL;
}
if (count > 1) {
/* Since the concatenation layer adds a small overhead we
* could try to figure out if the chips in cse0 and cse1 are
* identical and reprobe the whole cse0+cse1 window. But since
* flash chips are slow, the overhead is relatively small.
* So we use the MTD concatenation layer instead of further
* complicating the probing procedure.
*/
mtd_total = mtd_concat_create(mtds, count, "cse0+cse1");
if (!mtd_total) {
printk(KERN_ERR "%s and %s: Concatenation failed!\n",
map_cse0.name, map_cse1.name);
/* The best we can do now is to only use what we found
* at cse0. */
mtd_total = mtd_cse0;
map_destroy(mtd_cse1);
}
} else
mtd_total = mtd_cse0 ? mtd_cse0 : mtd_cse1;
return mtd_total;
}