Exemplo n.º 1
0
bool anyTrue(const double a[], int n)
{
    if (n <= 0)
        return false;
    if(somePredicate(a[n-1]))
        return true;
    return anyTrue(a, n-1);
}
Exemplo n.º 2
0
  // Return the subscript of the first element in the array for which
  // the somePredicate function returns true.  If there is no such
  // element, return -1.
int firstTrue(const double a[], int n)
{
    if (n <= 0)
    	return -1;

    int temp = firstTrue(a, n-1);
    if (somePredicate(a[n-1]) && temp == -1)
		    return n-1;
	  return temp;
}
Exemplo n.º 3
0
  // Return the number of elements in the array for which the
  // somePredicate function returns true.
int countTrue(const double a[], int n)
{
	if (n <= 0)
		return 0;

  int temp = countTrue(a+1, n-1);
	if (somePredicate(a[0]))
		return 1 + temp;
	return temp;
}
Exemplo n.º 4
0
int countTrue(const double a[], int n)
{
    int counter = 0;
    if(n > 0)
    {
        if(somePredicate(a[n-1]))
            counter++;
        counter += countTrue(a, n-1);
    }
    return counter;
    
}
Exemplo n.º 5
0
int firstTrue(const double a[], int n)
{
    int positionHolder = n-1;  //im returning the last negative number
    if(n > 0)
    {
        if(somePredicate(a[positionHolder]))
        {
            if(n == 1)
                return positionHolder;
            else if (firstTrue(a,n-1)== -1)
                return positionHolder;
            else
                return firstTrue(a, n-1);
        }
        else
            return firstTrue(a, n-1);
        
    }
    return -1;
}