Exemplo n.º 1
0
/*
 * 最大最大激励化 第 unitdx 个单元
 *
 */
double LayerWiseRBMs::maximizeUnit(int layerIdx, int unitIdx, double * unitSample, double argvNorm, int epoch){

    int AMnumIn = layers[0]->numVis;                                            

    // unitsample 归一化
    double curNorm = squareNorm(unitSample, AMnumIn, 1);
    cblas_dscal(AMnumIn, argvNorm / curNorm, unitSample, 1);
	
	double maxValue =0;

	for(int k=0; k<epoch; k++){
	// forward
		for(int i=0; i<=layerIdx; i++){
			if(i==0)
				layers[i]->setInput(unitSample);
			else
				layers[i]->setInput(layers[i-1]->getOutput());
			layers[i]->setBatchSize(1);
			layers[i]->runBatch();
		}
		maxValue = layers[layerIdx]->getOutput()[unitIdx];
	//back propagate
		for(int i=layerIdx; i>=0; i--){
			if(i==layerIdx)
				layers[i]->getAMDelta(unitIdx, NULL)	;
			else
				layers[i]->getAMDelta(-1, layers[i+1]->AMDelta);
		}
        double lr = 0.01 * cblas_dasum(AMnumIn, unitSample, 1) /                
                    cblas_dasum(AMnumIn, layers[0]->AMDelta, 1);
		
	// update unitSample
		cblas_daxpy(AMnumIn, lr, layers[0]->AMDelta, 1, unitSample, 1);
	//归一化 unitSample
		curNorm = squareNorm(unitSample, AMnumIn, 1);
	    cblas_dscal(AMnumIn, argvNorm / curNorm, unitSample, 1);
	
	}
	return maxValue;
}
Exemplo n.º 2
0
	/**
	 * Return inverse quaternion. In case of normalized quaternion: use conjugate method to get same result with better performance.
	 */
	template<class T> Quaternion<T> Quaternion<T>::inverse() const
	{
		T squaredNorm = squareNorm();
		return Quaternion<T>(-X/squaredNorm, -Y/squaredNorm, -Z/squaredNorm, W/squaredNorm);
	}