Exemplo n.º 1
0
int solve()
{
    sort(sticks, sticks + N);
    int hi = sticks[N - 1];

    int ans = 0;
    tree.init(sticks[N - 1]);

    for (int i = N - 4; i >= 2; --i) {
        int a = i + 1;
        for (int b = a + 1; b < N; ++b)
            for (int c = b + 1; c < N; ++c) {
                int v = max(1, sticks[c] - (sticks[a] + sticks[b]));
                tree.add(v, 1);
            }

        for (int j = i - 1; j >= 1; --j)
            for (int k = j - 1; k >= 0; --k) {
                int v = min(hi, sticks[i] + sticks[j] + sticks[k]);
                ans += tree.query(v - 1);
            }
    }

    return ans;
}
int main(){
   // freopen("input.txt", "r", stdin);
    Node lis[SZ];
    int n;
    int test, val, pos,  tc = 1;
    scanf("%d", &test);
    while( test-- ){
        scanf("%d", &n);
        for(int i = 1; i <= n; i++){
            scanf("%d", &val);
            lis[i] = Node(val, i);
        }
        sort(lis+1, lis+n+1);

        Bit bt = Bit(n);
        for(int idx = 1; idx <= n; idx++){
            pos = lis[idx].pos;
            bt.add(pos, 1 + bt.query(pos-1));
        }
        printf("Case %d: %lld\n", tc++, bt.query(n));
    }

    return 0;
}
Exemplo n.º 3
0
Arquivo: j.cpp Projeto: M4573R/pc-code
int main()
{
	int T;
	scanf("%d", &T);

	int ncase = 0;
	while (T--) {
		scanf("%d", &N);
		tree.init(N);
		for (int i = 1; i <= N; ++i) {
			int x;
			scanf("%d", &x);
			tree.add(i, x);
		}

		printf("Case %d:\n", ++ncase);
		scanf("%d", &M);
		while (M--) {
			int cmd;
			scanf("%d", &cmd);
			if (cmd == 1) {
				int x, y;
				scanf("%d%d", &x, &y);
				printf("%d\n", tree.query(x, y));
			}
			else if (cmd == 2) {
				int x, y, p;
				scanf("%d%d%d", &x, &y, &p);
				tree.add(x, -p);
				tree.add(y, p);
			}
		}
	}

	return 0;
}