Exemplo n.º 1
0
std::unique_ptr<GridSpan> GridResolvedPosition::resolveRowStartColumnStartNamedGridLinePositionAgainstOppositePosition(const GridResolvedPosition& resolvedOppositePosition, const GridPosition& position, const Vector<size_t>& gridLines)
{
    size_t gridLineIndex = std::max<int>(0, firstNamedGridLineBeforePosition(resolvedOppositePosition.toInt(), gridLines) - position.spanPosition() + 1);
    GridResolvedPosition resolvedGridLinePosition = GridResolvedPosition(gridLines[gridLineIndex]);
    if (resolvedGridLinePosition > resolvedOppositePosition)
        resolvedGridLinePosition = resolvedOppositePosition;
    return std::make_unique<GridSpan>(resolvedGridLinePosition, resolvedOppositePosition);
}
Exemplo n.º 2
0
std::unique_ptr<GridSpan> GridResolvedPosition::resolveGridPositionAgainstOppositePosition(const RenderStyle& gridContainerStyle, const GridResolvedPosition& resolvedOppositePosition, const GridPosition& position, GridPositionSide side)
{
    if (position.isAuto())
        return std::make_unique<GridSpan>(resolvedOppositePosition, resolvedOppositePosition);

    ASSERT(position.isSpan());
    ASSERT(position.spanPosition() > 0);

    if (!position.namedGridLine().isNull()) {
        // span 2 'c' -> we need to find the appropriate grid line before / after our opposite position.
        return resolveNamedGridLinePositionAgainstOppositePosition(gridContainerStyle, resolvedOppositePosition, position, side);
    }

    // 'span 1' is contained inside a single grid track regardless of the direction.
    // That's why the CSS span value is one more than the offset we apply.
    size_t positionOffset = position.spanPosition() - 1;
    if (isStartSide(side)) {
        size_t initialResolvedPosition = std::max<int>(0, resolvedOppositePosition.toInt() - positionOffset);
        return std::make_unique<GridSpan>(initialResolvedPosition, resolvedOppositePosition);
    }

    return std::make_unique<GridSpan>(resolvedOppositePosition, resolvedOppositePosition.toInt() + positionOffset);
}
Exemplo n.º 3
0
GridSpan GridResolvedPosition::resolveGridPositionAgainstOppositePosition(const ComputedStyle& gridContainerStyle, const GridResolvedPosition& resolvedOppositePosition, const GridPosition& position, GridPositionSide side)
{
    if (position.isAuto()) {
        if ((side == ColumnStartSide || side == RowStartSide) && resolvedOppositePosition.toInt())
            return GridSpan::definiteGridSpan(resolvedOppositePosition.prev(), resolvedOppositePosition);
        return GridSpan::definiteGridSpan(resolvedOppositePosition, resolvedOppositePosition.next());
    }

    ASSERT(position.isSpan());
    ASSERT(position.spanPosition() > 0);

    if (!position.namedGridLine().isNull()) {
        // span 2 'c' -> we need to find the appropriate grid line before / after our opposite position.
        return resolveNamedGridLinePositionAgainstOppositePosition(gridContainerStyle, resolvedOppositePosition, position, side);
    }

    return GridSpan::definiteGridSpanWithSpanAgainstOpposite(resolvedOppositePosition, position, side);
}
Exemplo n.º 4
0
GridSpan GridResolvedPosition::resolveNamedGridLinePositionAgainstOppositePosition(const ComputedStyle& gridContainerStyle, const GridResolvedPosition& resolvedOppositePosition, const GridPosition& position, GridPositionSide side)
{
    ASSERT(position.isSpan());
    ASSERT(!position.namedGridLine().isNull());
    // Negative positions are not allowed per the specification and should have been handled during parsing.
    ASSERT(position.spanPosition() > 0);

    const NamedGridLinesMap& gridLinesNames = gridLinesForSide(gridContainerStyle, side);
    NamedGridLinesMap::const_iterator it = gridLinesNames.find(position.namedGridLine());

    // If there is no named grid line of that name, we resolve the position to 'auto' (which is equivalent to 'span 1' in this case).
    // See http://lists.w3.org/Archives/Public/www-style/2013Jun/0394.html.
    if (it == gridLinesNames.end()) {
        if ((side == ColumnStartSide || side == RowStartSide) && resolvedOppositePosition.toInt())
            return GridSpan::definiteGridSpan(resolvedOppositePosition.prev(), resolvedOppositePosition);
        return GridSpan::definiteGridSpan(resolvedOppositePosition, resolvedOppositePosition.next());
    }

    return GridSpan::definiteGridSpanWithNamedSpanAgainstOpposite(resolvedOppositePosition, position, side, it->value);
}