int main() {
  int n, q;
  scanf("%d%d", &n, &q);
  memset(&tree, 0, sizeof(tree));
  for(int i = 1; i <= n; i++)
    scanf("%d", &A[i]);
  tree.build(1, 1, n);

  int k, args[20], original[20];
  char cmd[100];
  while(q--) {
    scanf("%s", cmd);

    // 解析输入
    int len = strlen(cmd);
    k = 0; args[k] = 0;
    for(int i = 6; i < len; i++)
      if(isdigit(cmd[i])) args[k] = args[k] * 10 + cmd[i] - '0';
      else { k++; args[k] = 0; }

    // 处理命令
    if(cmd[0] == 'q') {
      qL = args[0]; qR = args[1];
      printf("%d\n", tree.query(1, 1, n));
    } else {
      for(int i = 0; i < k; i++) original[i] = A[args[i]];
      for(int i = 0; i < k; i++) {
        p = args[i];
        v = A[p] = original[(i+1)%k];
        tree.update(1, 1, n);
      }
    }
  }
  return 0;
}
Exemplo n.º 2
0
int main() {
  int n, m;
  while(scanf("%d%d", &n, &m) == 2) {
    memset(&tree, 0, sizeof(tree));
    while(m--) {
      scanf("%d", &op);
      if(op == 1) {
        scanf("%d%d", &p, &v);
        tree.update(1, 1, n);
      } else {
        scanf("%d%d", &qL, &qR);
        printf("%d\n", tree.query(1, 1, n));
      }
    }
  }
  return 0;
}