int main(){
	while(scanf("%d",&N) == 1 && N){
		int sum = 0,ans = INT_MAX,cmax = 0;
		L.resize(N);
		taken.resize(N);
		loop(i,N) {
			scanf("%d",&L[i]);
			sum += L[i];
			cmax = max(cmax,L[i]);
			taken[i] = 0;
		}
		sort(all(L));
		for(int i = sum;i>=1;i--){
			if(sum%i == 0){
				int l = sum/i,n = i;
				if(l >= cmax){
					fill(all(taken),0);
					bool c = possibe(0,0,0,l,n);
					if(c){
						ans = l;
						break;
					} 
				}		
			}
		}
		printf("%d\n",ans);
	}  	
 // Constructs the lookup table in O(V log V) time and memory
 lowest_common_ancestor(const vvi& tree = {}, int root = 0) {
     depth.resize(tree.size());
     pos.resize(tree.size());
     vector<visit> tour;
     if (tree.size()) dfs(tree, tour, root, root);
     euler = sparse_table<visit>(tour);
 }
Exemplo n.º 3
0
int main(){
    freopen("1199.txt", "r", stdin);
    //setbuf(stdout, NULL);
    scanf("%d", &N);
    adj = vvi(N, vi(N));
    int total_edge = 0;
    in_degree.resize(N); out_degree.resize(N);
    for(int i = 0; i < N; i++){
        for(int j = 0; j < N; j++){
            scanf("%d", &adj[i][j]);
            out_degree[i] += adj[i][j];
            in_degree[j] += adj[i][j];
        }
    }
    bool flag = false;
    for(int i = 0; i < N; i++){
        if( (out_degree[i] & 1) || (in_degree[i] & 1)){
            flag = true;
            break;
        }
    }

    if(flag){
        printf("-1\n");
    }
    else{
        vi trace;
        solve(0, trace);
        for(int i = 0; i < trace.size(); i++){
            printf("%d ", trace[i] + 1);
        }
        printf("\n");
    }
    
}
Exemplo n.º 4
0
    heavy_light(const vvi &graph, int root) {
        links = lca(graph, 0);

        st = seg_tree<T>(graph.size());
        index.resize(graph.size()), jump.resize(graph.size());
        dfs(root, root, root, graph);
    }
Exemplo n.º 5
0
int main(){
  int N, M, a, b, c;
  while(cin >> N >> M && N != 0 && M != 0){
    AdjList.resize(N);
    dfs_num.resize(N);
    visited.resize(N);
    dfs_low.resize(N);
    numSCC = dfsNumberCounter = 0;

    for(int i = 0; i < M; i++){
      cin >> a >> b >> c;
      AdjList[a-1].push_back(b-1);
      if(c == 2) AdjList[b-1].push_back(a-1);
    }

    for(int i = 0; i < N; i++)
      if(dfs_num[i] == 0)
	tarjan(i);

    if(numSCC == 1) cout << 1 << endl;
    else cout << 0 << endl;

    visited.clear();
    AdjList.clear();
    dfs_low.clear();
    dfs_num.clear();
    S.clear();
  }
}
int main() {
    int tc;
    cin >> tc;
    while (tc--) {
        int n, m;
        cin >> n >> m;
        AdjList.clear(); AdjList.resize(n);
        for (int i = 0; i < m; i++) {
            int a, b;
            cin >> a >> b;
            AdjList[a].push_back(ii(b, 0));
        }
        bool cac = true;
        int numScc = 0;
        dfs_num.clear(); dfs_num.resize(n, UNVISITED);
        dfs_parent.clear(); dfs_parent.resize(n, 0);
        for(int i = 0; i < n; i++) {
            if(dfs_num[i] == UNVISITED) {
                numScc++;
                if(graphCheck(i)) {
                    cac = false;
                    break;
                }
            }
        }
        if(cac && numScc == 1) cout << "YES\n";
        else cout << "NO\n";
    }
    return 0;
}
void init() {
	pertenece.resize(n);
	rank.resize(n, 0);
	size.resize(n, 1);
	for(int i = 0; i < n; i++) {
		pertenece[i] = i;
	}
}
Exemplo n.º 8
0
 Task(int _tl, int _testsCnt) {
     tl = _tl;
     testsCnt = _testsCnt;
     averages.resize(testsCnt + 1, 0);
     counters.resize(testsCnt + 1, 0);
     sums.resize(testsCnt + 1, 0);
     averages[testsCnt] = (tl / AVG_CONST) * testsCnt;
 }
Exemplo n.º 9
0
void scc () {
	nr.resize (gr.size (), -1);
	low.resize (gr.size ());
	inst.resize (gr.size (), false);
	for (int i = 0; i < gr.size (); ++i) {
		if (nr[i] < 0) {
			visit (i);
		}
	}
}
Exemplo n.º 10
0
void init(int n) {
	h.resize(n, -1);
	par.resize(n, -1);
	//add 1
	vi v1; v1.pb(1);
	Node z1(1, 1, 0, v1);
	G1.pb(z1);
	h[1] = 1;
	h[0] = 0;
}
int main () {
    #ifndef ONLINE_JUDGE
    freopen(INP, "r", stdin); freopen(OUT, "w", stdout);
    #endif
    
    scanf("%d", &n);
    order.clear();
    arr1.assign(n+1,0);
    a1.clear();
    FOR(i,1,n) scanf("%d", &a), a1.pb(a);
    REP(i,n) arr1[a1[i]-1] = i+1;
    REP(i,n) order[arr1[i]] = i;
    while(scanf("%d", &a) != EOF){
        arr.assign(n+1,0);
        a2.clear();
        a2.pb(a);
        ans.resize(0);
        len = 0;
        FOR(i,1,n-1) scanf("%d", &a), a2.pb(a);
        REP(i,n) arr[a2[i]-1] = i+1;
        REP(i,n) updateLis(arr[i]);   
        cout << len << endl; 
    }

    return 0;
}
Exemplo n.º 12
0
 void clear()
 {
     dfs_num.clear();
     dfs_num.resize(v+1);
     connectedComp.clear();
     cnt = 0;
 }
Exemplo n.º 13
0
// calculates the "male optimal" stable marriage (i.e. there
// is no stable marriage where any man prefers his match
// over the one given here) a female optimal matching can be
// found by swapping men and women
// mpref: vector i is the list of i's preferred partners, in
//    *decreasing* order of preference (0 indexed)
// fpref: as above, but for women
// match: a vector (passed in with any size) filled so that
//    position i gives the man matched with woman i
void stable_marriage(const vvi& mpref, const vvi& fpref,
           vi& match) {
  // initially no one matched
  match.resize(mpref.size(), -1); 

  // get a map from (w, m) to w's "rank" for m
  vvi fmap(match.size(), vi(match.size()));
  for(int i = 0; i < match.size(); ++i)
    for(int j = 0; j < match.size(); ++j)
      fmap[i][fpref[i][j]] = j;

  vi next_prop(match.size(), 0);
  queue<int> mfree;
  for(int i = 0; i < match.size(); ++i)
    mfree.push(i);

  while(!mfree.empty()) {
    const int m = mfree.front();
    const int w = mpref[m][next_prop[m]];
    mfree.pop();

    if(match[w] == -1) {
      match[w] = m;
    }
    else if(fmap[w][match[w]] > fmap[w][m]) {
      mfree.push(match[w]);
      match[w] = m;
    }
    else if(++next_prop[m] < match.size()) {
      mfree.push(m);
    }
  }
}
Exemplo n.º 14
0
int main()
{
	ifstream fin("marathon.in");
	ofstream fout("marathon.out");

	int N; 
	fin >> N;
	points.resize(N);
	for (int i = 0; i < N; ++i)
	{
		fin >> points[i].first >> points[i].second;
	}

	T.resize(N - 2);
	res.resize(N - 2);

	T[0].first = 0;
	T[0].second =  dist_cont(2, N-1);
	res[0] = T[0].first + T[0].second + dist_two(0, 2);
	int result = res[0];

	for (int k = 1; k <= N - 3; ++k)
	{
		T[k].first = T[k - 1].first + dist_two(k - 1, k);
		T[k].second = T[k - 1].second - dist_two(k + 1, k+2);
		res[k] = T[k].first + T[k].second + dist_two(k, k + 2);
		result = min(result, res[k]);
	}
	fout << result << '\n';
	
	return 0;
}
int main() {
    ios::sync_with_stdio(0);
    double d;
    int m, tc = 1;
    while( cin >> d >> m) {
        cout << "Case " << tc++ << ":" << endl;
        memo.clear(); memo.resize(105, -1);
        prices.clear(); prices.resize(m + 1);
        prices[0].first = 1; prices[0].second = (d + eps) * 100;
        for(int i = 1; i <= m; i++) {
            int tmp; cin >> tmp >> d;
            prices[i].first = tmp; prices[i].second = (d + eps) * 100;
        }
        string str;
        cin.get();
        getline(cin, str);
        stringstream ss(str);
        int tmp;
        while(ss >> tmp) {
            cout << "Buy " << tmp << " for $" << fixed << setprecision(2) << (double)solve(tmp) / 100 << endl;
        }
    }

    return 0;
}
Exemplo n.º 16
0
int main(void) {
  std::ios_base::sync_with_stdio (false);
  size_t n;
  cin >> n >> ws;
  vvs graph(n, vs());

  dfs_num.resize(n, 0);
  parent.resize(n, -1);
  finished = false;
  a = b = c = -1;

  string line;
  for (size_t line_cnt = 0; line_cnt < n; line_cnt++) {
    getline(cin, line);
    for (size_t char_cnt = 0; char_cnt < n; char_cnt++) {
      if (line.at(char_cnt) == '1')
	graph[line_cnt].push_back(char_cnt);
    }
  }
  for (size_t counter = 0; counter < n; counter++)
    if (!dfs_num[counter])
      dfs(graph, counter);
  if (a >= 0)
    cout << a+1 << " " << b+1 << " " << c+1 << endl;
  else
    cout << -1 << endl;

  return 0;
}
int maxFlow() {
    int result = 0;
    while(dinic_bfs()) {
        work.clear(); work.resize(n, 0);
        while(int d = dinic_dfs(s, inf)) result += d;
    }
    return result;
}
Exemplo n.º 18
0
 Solution(int _taskNum) {
     taskNum = _taskNum;
     curTest = sum = testsComplete = 0;
     testStart.resize(task[taskNum].testsCnt);
     average = task[taskNum].averages.back();
     if (DEBUG) cerr << "new solution with average = " << average << endl;
     counted = false;
 }
void blmnfrd() {
    dist.clear();
    dist.resize(n, -inf);
    dist[0] = 100;
    for (int i = 0; i < n - 1; ++i)
        for (int j = 0; j < n; ++j)
            for (auto k : vec[j])
                if (dist[j] + k.first > 0)
                    dist[k.second] = max(dist[k.second], dist[j] + k.first);
}
Exemplo n.º 20
0
int main() {
	int n ;
	cin >> n;
	position.resize(n+1) ;
	edges.resize(n+1) ;
	int a, b, c ;
	rep(i,n) {
		cin >> a >> b >> c;
		edges[a].left = b , edges[a].right = c ;
	}
Exemplo n.º 21
0
inline void get_visited(vi & visited, vi & states)
{
    states.resize(0);
    for(int i = 0; i != visited.size(); i++) {
        if(visited[i]) { 
            states.push_back(i);
            visited[i] = white;
        }
    }
}
Exemplo n.º 22
0
int main()
{
	
	s(N) ; s(K) ;
	pos.resize(N);
	rep(0,N-1,i) s(pos[i]) ;
	sort(pos.begin() , pos.end());
	p(solve(0,100000000));
	return 0;
}
Exemplo n.º 23
0
int main(){
    ios::sync_with_stdio(0);
    int count=0;
    while(cin >> n && n){
        cout << "**********************************************************\n";
        cout << "Network #"<<++count << endl;
        dist.clear();
        dist.resize(n,vd(n));
        memset(memo,-1,sizeof memo);
        X.clear();X.resize(n);
        Y.clear();Y.resize(n);
        for (int i = 0; i < n; ++i) {
            cin >> X[i] >> Y[i];
        }
        for (int j = 0; j < n; ++j) {
            for (int i = j+1; i < n; ++i) {
                dist[j][i]= dist[i][j] = dis(j,i);
                //cerr << "dist " << j << "  " << i <<"  ->   "<< dist[j][i] << endl;
            }
        }

        double ans = inf; int id =-1;
        for (int k = 0; k < n; ++k) {
            double val = tsp(k,(1<<k));
            //cerr << val << endl;
            if(val < ans) ans = val,id=k;
        }
        //id=0;
        //cerr << id << endl;
        int msk=0;
        while(--n) {
                msk |= (1 << id);
            if(dis(id,par[id][msk])!=16) {
                printf("Cable requirement to connect (%d,%d) to (%d,%d) is %.2lf feet.\n", X[id], Y[id], X[par[id][msk]], Y[par[id][msk]], dis(id, par[id][msk]) );
                id = par[id][msk];
            }
        }
        printf("Number of feet of cable required is %.2lf.\n",ans);
    }

    return 0;
}
Exemplo n.º 24
0
int solve(){
	dp.resize(v.size());
	dp[0]=v[0];
	int maxi=dp[0];
	for(int i=1;i<dp.size();i++){
		if(dp[i-1]>0)dp[i]=dp[i-1]+v[i];
		else dp[i]=v[i];
		maxi=max(maxi,dp[i]);
	}
	return maxi;
}
Exemplo n.º 25
0
void generateMapping(int r1, int r2) {
map.resize(n);
map[r1] = r2 - n;
sort(children[r1].begin(), children[r1].end(), compare);
sort(children[r2].begin(), children[r2].end(), compare);
for (int i = 0; i < (int) children[r1].size(); i++) {
int u = children[r1][i];
int v = children[r2][i];
generateMapping(u, v);
}
}
int main(){

    ios::sync_with_stdio(0);

    while(cin >> n && (n != -1)) {
        vec.clear();
        vec.resize(n);
        int enrgy, b, num;
        for (int i = 0; i < n; ++i) {
            cin >> enrgy >> num;
            for (int j = 0; j < num; ++j) {
                cin >> b;
                vec[i].push_back(ii(enrgy, b - 1));
            }
        }
        blmnfrd();
        vis.clear(); vis.resize(n , 0);
        dfs(0);
        vi vis1 = vis;

        if(dist[n - 1] > 0) cout << "winnable" << endl;
        else {
            bool happen = false;
            for (int i = 0; i < n && !happen; ++i)
                for (auto j : vec[i])
                    if (dist[j.second] < dist[i] + j.first && dist[i] + j.first > 0) {
                        vis.clear(); vis.resize(n,0);
                        dfs(i);
                        if (vis[n - 1] && vis1[i]) {
                            happen = true;
                            break;
                        }
                    }
            //if(chk())  cout << "winnable" << endl;
            if (happen) cout << "winnable" << endl;
            else cout << "hopeless\n";
        }
    }

    return 0;
}
Exemplo n.º 27
0
int main(){


    ios::sync_with_stdio(0);
    int door,w,a;
    while(cin >> n && (n!=-1)){
        adjlist.clear();
        adjlist.resize(n);
        vis.clear(); vis.resize(n,0);
        for (int i = 0; i < n; ++i) {
            cin >> w >> door;
            while(door--){
                cin >> a;
                adjlist[i].push_back(ii(a-1,w));
            }
        }
        bellmanFord();

        if(dist[n-1] > 0) cout << "winnable\n";
        else{
            bool haspos = false;
            for (int i = 0; i < n && !haspos; ++i) {
                for(auto & e: adjlist[i]){
                    if(dist[i] + e.second > 0 && dist[e.first] < dist[i] + e.second){
                        vis.clear(); vis.resize(n,0);
                        dfs(i);
                        if(vis[n-1] ){
                            haspos = true;
                            break;
                        }
                    }
                }
            }
            if(haspos) cout << "winnable\n";
            else cout << "hopeless\n";
        }
    }

    return 0;
}
Exemplo n.º 28
0
Arquivo: A.cpp Projeto: Igorjan94/CF
void run()
{
    readln(n);
    a.resize(n, -1);
    int x;
    fori(n - 1)
        readln(x),
        a[x - 1] = 1;
    fori(n)
        if (a[i] == -1){
            writeln(i + 1);
            return;}
}
int lis(const vl& in, vi& liss, vi& parents) {
  // position j gives index of the last element in "best"
  // known lis of length j (where best means ends in
  // smallest element)
  vi length_idx(in.size() + 1, -1);
  // position i gives the immediate predecessor of element i
  // in best known lis
  parents.resize(in.size(), -1);
  // gives the length of the best known lis ending in pos i 
  liss.resize(in.size(), -1);

  // best known length
  int L = 0;

  for(int i = 0; i < in.size(); ++i) {
    // binary search for largest pos j <= L s.t.
    // in[length_idx[j]] < in[i]
    // i.e. the lis we can append in[i] onto
    int low = 1, high = L;
    while(low <= high) {
      int mid = ceil((low+high)/2);

      if(in[length_idx[mid]] < in[i])
        low = mid+1;
      else
        high = mid-1;
    }

    // low is length of lis ending in in[i]
    parents[i] = length_idx[low-1];
    length_idx[low] = i;
    liss[i] = low;

    // update best known length
    L = max(L, low);
  }

  return L;
}
bool dinic_bfs() {
    dist.clear(); dist.resize(n, -1); dist[s] = 0;
    queue<int> queue1; queue1.push(s);
    while(!queue1.empty()) {
        int u = queue1.front(); queue1.pop();
        for(auto &e : graph[u]) {
            if(dist[e] != -1 || rem[u][e] <= 0) continue;
            dist[e] = dist[u] + 1;
            queue1.push(e);
        }
    }
    return (dist[t] != -1);
}