int main()
{
int size;
scanf("%d", &size);
float * heights = (float*)malloc(size * sizeof(float));
int i;
for(i = 0; i < size; ++i)
{
scanf("%f", &heights[i]);
}
int * asc = (int*)malloc(size * sizeof(int));
LIS(heights, size, asc);
float * reverse_heights= (float*)malloc(size * sizeof(float));
for(i = 0; i < size; ++i)
{
reverse_heights[i] = heights[size - 1 - i];
}
int * desc = (int*)malloc(size * sizeof(int));
LIS(reverse_heights, size, desc);
//for(i = 0; i < size; ++i)
//{
// printf("%d\t", asc[i]);
//}
//printf("\n");
//for(i = 0; i < size; ++i)
//{
// printf("%d\t", desc[i]);
//}
//printf("\n");
int max = INT_MIN;
int j;
for(i = 0; i < size - 1; ++i)
{
for(j = size - 2 - i; j >= 0; --j)
{
if(asc[i] + desc[j] > max)
{
max = asc[i] + desc[j];
}
}
}
printf("%d\n", size - max);
free(asc);
free(desc);
free(heights);
free(reverse_heights);
return 0;
}
int main(void) {
int n;
scanf("%d", &n);
int array[MAX_LEN];
for (int i = 0; i < n; i++) {
scanf("%d", &array[i]);
}
node dp[MAX_LEN];
for (int i = 0; i < n; i++)
dp[i].length = 1;
LIS(array, dp, n);
int max = dp[0].length;
for (int i = 1; i < n; i++) {
if (max < dp[i].length) {
max=dp[i].length;
}
}
for (int i = 0; i < n; i++) {
if (dp[i].length == max) {
for (int j = 0; j < max; j++) {
printf("%d ", dp[i].a[j]);
}
printf("\n");
}
}
}
int main()
{
int n, i, missle[N], lis[N];
char str[10];
bool first = true;
scanf("%d", &n);
getchar();
getchar();
while (n--)
{
if (first)
first = false;
else
putchar('\n');
i = 0;
while (gets(str) && str[0])
missle[i++] = getNum(str);
int len = LIS(missle, i, lis);
printf("Max hits: %d\n", len);
for (i = 0; i < len; i++)
printf("%d\n", lis[i]);
}
return 0;
}
int main()
{
int n, dim, temp[10], i;
Box box[N];
while (scanf("%d%d", &n, &dim) != EOF)
{
int lis[N] = {};
for (int k = 0; k < n; k++)
{
box[k].D = dim;
box[k].tag = k + 1;//第0個盒子編號是1
for (i = 0; i < dim; i++)
scanf("%d", &box[k].dim[i]);
//將各維度由小到大排序
std::sort(box[k].dim, box[k].dim + dim);
}
//將箱子由小排到大
std::sort(box, box + n, comp);
int len = LIS(box, n, lis);
//output
printf("%d\n", len);
for (i = 0; i < len - 1; i++)
printf("%d ", lis[i]);
printf("%d\n", lis[i]);
}
return 0;
}
int main()
{
int ar[]={10,22,9,33,21,50,41,60,80};
int n=sizeof(ar)/sizeof(ar[0]);
printf("lIS length is %d",LIS(ar,n));
return 0;
}
int main(int argc, char *argv[])
{
int a[] = { 10, 22, 9, 33, 21, 50, 41, 60 };
int size = sizeof(a)/sizeof(a[0]);
printf("Longest Increasing Subsequence = %d\n",LIS(a,size));
}
void LISmain(void){
int nums[] = //{1,2,3,4,5,5,3,2,5,6,7,4};
//{35, 36, 39, 3, 15, 27, 6, 42};
//{5, 4, 3, 2, 1};
{1, -1, 2, -2, 0, 1, 1};
int len = sizeof(nums)/sizeof(nums[0]);
printf("%d\n", LIS(nums, len));
}
int main()
{
int arr[] = {1,-1,2,-3,4,-5,6,-7 };
printf("%d\n", LIS(arr,sizeof(arr)/sizeof(int)));
outputLIS( arr, sizeof(arr) / sizeof(int) - 1);
printf("\n");
return 0;
}
int main()
{
int n;
while (scanf("%d", &n)!=EOF)
{
BuildSeqAndInitDP(n);
printf("%d\n", LIS(n));
}
return 0;
}
void Assembler::asm_li(Register r, int32_t imm) {
#if !PEDANTIC
if (isS16(imm)) {
LI(r, imm);
return;
}
if ((imm & 0xffff) == 0) {
imm = uint32_t(imm) >> 16;
LIS(r, imm);
return;
}
int main()
{
int size;
scanf("%d", &size);
int *sequence = (int*)malloc(sizeof(int) * size);
int i;
for(i = 0; i < size; ++i)
scanf("%d", &sequence[i]);
printf("%d\n", LIS(sequence, size) );
free(sequence);
return 0;
}
/**
Index value of longest increasing subsequence in O(n^2) - Recursively with dp apporoach.
Ultimately this recursive approach is not better than iterative as
all sub problems are revisited.
**/
int LIS(int i) {
if(i == 0) return 1;
if (dp[i] != -1) {
return dp[i];
}
int ans = 1;
for(int j = 0; j < i; j++) {
if (x[i] > x[j]) {
ans = max(ans, 1 + LIS(j));
}
}
return dp[i] = ans;
}
int main(int argc, char *argv[])
{
int t;
scanf("%d",&t);
while(t--)
{
scanf("%d",&n);
for(int i=1;i<=n;++i)
{
scanf("%d",&a[i]);
}
printf("%d\n", LIS());
}
return 0;
}
int main(){
int *a,i, elem;
printf("Enter no of elements\n");
scanf("%d", &elem);
a = (int*)malloc(sizeof(int)*elem);
printf("Enter elements\n");
for(i=0;i<elem;i++){
scanf("%d", &a[i]);
}
printf("Longest Decresing Subsequence=%d\n", LIS(a, elem));
return 0;
}
bool increasingTriplet(vector<int>& nums) {
return LIS(nums) >= 3;
}
//Seja S o conjunto de todas las sequencias dos n primeiros números naturais.
//Defina R(s), com s \in S o conjunto de todas as sequencias que podem
//ser geradas rotacionando S.
//Defina LIS(s) e LDS(s) como você sabe e sejam |LIS(s)| e |LDS(s)| suas
//cardinalidades.
//Determinar Max_{s \in S}(Min_{s' \in R(s)}(Min(|LIS(s)|, |LDS(s)|)))
int main(int argc, char* argv[]){
char* vector;
char* vecRotation;
int length = atoi(argv[1]);
// int lR_expected = atoi(argv[2]);
int num_expected = 0;
clock_t start,end;
vector = (char*) malloc(length);
vecRotation = (char*) malloc(length);
start = clock();
unsigned int lmaxS = 0;
//Length -1 porque devido a rotação pode sempre deixar o primeiro número fixo, e alternar os seguintes
//Dividido por 2, porque a inversão cobre metade do conjunto.
unsigned long long counter = fatorial(length-1)/2;
unsigned long long index = 0;
//Cada loop gera um conjunto de sequências. Elementos de S. Cada elemento possui um conjunto de R sequencias.
unsigned int lLIS, lLDS;
while(counter > index){
index++;
counter--;
getSequence(vector, length, index);
//printf("%llu --> ", index);
//printVector(vector, length);
unsigned int lminR = length;
lminR = LIS(vector, length);
if(lminR <= lmaxS)
continue;
lLDS = LDS(vector, length);
if(lLDS < lminR)
lminR = lLDS;
if(lLDS <= lmaxS)
continue;
memcpy(vecRotation,vector,length);
int i;
for(i = 0; i < length-1; i++){
rotation(vecRotation, length);
lLIS = LIS(vecRotation, length);
if(lLIS < lminR)
lminR = lLIS;
if(lLIS <= lmaxS)
break;
lLDS = LDS(vecRotation, length);
if(lLDS < lminR)
lminR = lLDS;
if(lLDS <= lmaxS)
break;
}
//Define o maior valor encontrado entre os elementos de S
if(lmaxS < lminR){
lmaxS = lminR;
}
}
end = clock();
printf("%d -> Tempo: %f s\n",length, (float)(end-start)/CLOCKS_PER_SEC);
printf("Lmax S = %d\n",lmaxS);
free(vector);
free(vecRotation);
}
void work(){
LIS();
int res=0;
for(int i=1;i<=n;i++) res=max(res,f[i]);
printf("%d\n",res);
}
