void analyst::analysis(class matcher &M) {
map <int, int> correct_match;
int * deg_a = new int[M.G_a->num_nodes+1];
int * deg = new int[M.G->num_nodes+1];
FILE * in = fopen("./data/100\%/pair_a_c.txt", "r");
for (int i, j; fscanf(in, "%d%d", &i, &j) == 2; correct_match[j]=i);
fclose(in);
calc_degree(*(M.G_a), deg_a);
calc_degree(*(M.G), deg);
vector<match_edge> match_edges;
char * flag_a = new char[MAX_NODES], * flag = new char[MAX_NODES];
memset(flag_a, 0, MAX_NODES);
memset(flag, 0, MAX_NODES);
for (int i=1; i <= M.G_a->num_nodes; i++)
for (int j=1; j <= M.G->num_nodes; j++)
match_edges.push_back(match_edge(i, j, M.sim_nodes[i][j]));
sort(match_edges.begin(), match_edges.end());
vector <double> seq;
FILE * ana = fopen("analysis.txt", "w");
for (int i=0; i < M.ans_pairs.size(); i++) {
if (M.ans_pairs[i].u != correct_match[M.ans_pairs[i].v])
fprintf(ana, "@@@\t");
fprintf(ana, "Node \t%d (a: \t%d) \tDegree \t%d (\t%d) match with a_node \t%d (deg \t%d): \t%g",
M.ans_pairs[i].v,
correct_match[M.ans_pairs[i].v],
deg[M.ans_pairs[i].v],
deg_a[correct_match[M.ans_pairs[i].v]],
M.ans_pairs[i].u,
deg_a[M.ans_pairs[i].u],
M.ans_pairs[i].w
);
seq.clear();
for (int j=1; j<=M.G_a->num_nodes; j++)
if (!flag_a[j])
seq.push_back(M.sim_nodes[j][M.ans_pairs[i].v]);
flag_a[M.ans_pairs[i].u] = 1;
flag[M.ans_pairs[i].v] = 1;
sort(seq.begin(), seq.end());
int k = 0;
for (; k<seq.size() && seq[k] <= M.ans_pairs[i].w + 1e-6; k++);
fprintf(ana, " (No. \t%d, score \t%g/%g)", (int)seq.size()-k+1, seq[k-1], seq[seq.size()-1]);
fprintf(ana, "\n");
}
fclose(ana);
delete []deg_a;
delete []deg;
delete []flag_a;
delete []flag;
}
int main() {
double i,j;
nmk1 = calc_degree(N1, M1, K1_MIN);
nmk2 = calc_degree(N2, M2, K2_MIN);
for(i=K1_MIN; i<K1_MAX; i+=1.0) {
for(j=K2_MIN; j<K2_MAX; j+=1.0) {
calc_xy(i, j);
printf("%lf, %lf, %lf, %lf\n", i, j, X, Y);
}
}
}
//正向计算
void calc_xy(double k1, double k2) {
double d1 = calc_degree(N1, M1, k1) - nmk1;
double d2 = calc_degree(N2, M2, k2) - nmk2;
double x = sin(d1)*B;
double y = cos(d1)*B+D;
double dt = PI - d1 -d2;
X = x+sin(dt)*C;
Y = y-cos(dt)*C;
if(d1 > PI/3*2 && d2 > PI/3*2) {
X = 0;
Y = 0;
}
}
