Пример #1
0
// display code
static void DisplayErrorCode(int length, int code) {
	// todo: I suggest we use 'itoa' method to simplify this logic
	for (int iter = length - 1; iter >= 0; iter--) {
		int ourDigit = (int) efiPow10(iter);		// 10^0 = 1, 10^1 = 10, 10^2=100, 10^3 = 1000, ....
		int digit = 1;						// as we remember "0" we show as one blink
		while (code >= ourDigit) {
			code = code - ourDigit;
			digit++;
		}
		if (iter % 2 == 0)
			blink_digits(digit, MFI_SHORT_BLINK);		// even 2,0 - long blink
		else
			blink_digits(digit, MFI_LONG_BLINK); 		// odd  3,1 - short blink
	}
}
Пример #2
0
int efiPow10(int param) {
	switch (param) {
	case 0:
		return 1;
	case 1:
		return 10;
	case 2:
		return 100;
	case 3:
		return 1000;
	case 4:
		return 10000;
	case 5:
		return 100000;
	case 6:
		return 1000000;
	case 7:
		return 10000000;
	case 8:
		return 100000000;
	}
	return 10 * efiPow10(10 - 1);
}