Пример #1
0
int remove_entry_from_dir(struct ref_dir *dir, const char *refname)
{
	int refname_len = strlen(refname);
	int entry_index;
	struct ref_entry *entry;
	int is_dir = refname[refname_len - 1] == '/';
	if (is_dir) {
		/*
		 * refname represents a reference directory.  Remove
		 * the trailing slash; otherwise we will get the
		 * directory *representing* refname rather than the
		 * one *containing* it.
		 */
		char *dirname = xmemdupz(refname, refname_len - 1);
		dir = find_containing_dir(dir, dirname, 0);
		free(dirname);
	} else {
		dir = find_containing_dir(dir, refname, 0);
	}
	if (!dir)
		return -1;
	entry_index = search_ref_dir(dir, refname, refname_len);
	if (entry_index == -1)
		return -1;
	entry = dir->entries[entry_index];

	MOVE_ARRAY(&dir->entries[entry_index],
		   &dir->entries[entry_index + 1], dir->nr - entry_index - 1);
	dir->nr--;
	if (dir->sorted > entry_index)
		dir->sorted--;
	free_ref_entry(entry);
	return dir->nr;
}
Пример #2
0
/*
 * Clear and free all entries in dir, recursively.
 */
static void clear_ref_dir(struct ref_dir *dir)
{
	int i;
	for (i = 0; i < dir->nr; i++)
		free_ref_entry(dir->entries[i]);
	FREE_AND_NULL(dir->entries);
	dir->sorted = dir->nr = dir->alloc = 0;
}
Пример #3
0
void    free_ref_dict( ref_entry * * dict )
{
    ref_entry   *   wk;
    ref_entry   *   wkn;

    wk = *dict;
    while( wk != NULL ) {
        wkn = wk->next;
        free_ref_entry( dict, wk );
        wk = wkn;
    }
    *dict = NULL;                       // dictionary is empty
    return;
}
Пример #4
0
/*
 * Sort the entries in dir non-recursively (if they are not already
 * sorted) and remove any duplicate entries.
 */
static void sort_ref_dir(struct ref_dir *dir)
{
	int i, j;
	struct ref_entry *last = NULL;

	/*
	 * This check also prevents passing a zero-length array to qsort(),
	 * which is a problem on some platforms.
	 */
	if (dir->sorted == dir->nr)
		return;

	QSORT(dir->entries, dir->nr, ref_entry_cmp);

	/* Remove any duplicates: */
	for (i = 0, j = 0; j < dir->nr; j++) {
		struct ref_entry *entry = dir->entries[j];
		if (last && is_dup_ref(last, entry))
			free_ref_entry(entry);
		else
			last = dir->entries[i++] = entry;
	}
	dir->sorted = dir->nr = i;
}
Пример #5
0
void free_ref_cache(struct ref_cache *cache)
{
	free_ref_entry(cache->root);
	free(cache);
}