int indexOfMin(const double a[], int n)
{
if(n <= 0)
return -1;
if(n == 1)
return n-1;
if(a[n-1] < a[indexOfMin(a, n-1)])
{
return n-1;
}
else
{
return indexOfMin(a, n-1);
}
}
// Return the subscript of the smallest element in the array (i.e.,
// the one whose value is <= the value of all elements). If more
// than one element has the same smallest value, return the smallest
// subscript of such an element. If the array has no elements to
// examine, return -1.
int indexOfMin(const double a[], int n)
{
if (n <= 0) return -1;
if (n == 1) return 0;
int temp = indexOfMin(a+1, n-1) + 1;
if (a[0] > a[temp])
return temp;
return 0;
}
